Question

我有一张桌子，我想要得到：

ID  Name    Stock   Code    Date
<---------------------------------------------->
123 GAME_0011     1     WK1 2018-11-20 16:12:16
120 GAME_0088     212   WK1 2018-11-20 19:32:13
109 GAME_0088     21    WK1 2018-11-20 19:32:13
101 GAME_0088     20    WK1 2018-11-20 14:00:41
105 GAME_0011     1     WK1 2018-11-20 14:00:41
102 GAME_0088     2     WK1 2018-11-20 14:00:41

结果将是按名称，代码以及每个date字段的最大值，如果日期相同，也将按id进行过滤：

ID  Name    Stock   Code    Date
<---------------------------------------------->
120 GAME_0088     212   WK1 2018-11-20 19:32:13
123 GAME_0011     1     WK1 2018-11-20 16:12:16

我的查询是：

SELECT *
FROM games
WHERE name IN ('GAME_0088', 'GAME_0011')
AND code IN ('WK1')
AND date IN (SELECT max(date) FROM stocks GROUP BY name)
ORDER BY id desc

但是返回：

ID  Name    Stock   Code    Date
<---------------------------------------------->
123 GAME_0011   1   WK1 2018-11-20 16:12:16
109 GAME_0088   21  WK1 2018-11-20 19:32:13

怎么了？我也该如何通过MAX ID进行过滤？

Answer 1

在派生表中，可以为ID和name的特定组获取code的最大值。使用此信息重新加入games表，以获取对应于最大日期的行。

SELECT g.*
FROM games AS g 
JOIN 
( SELECT name, code, MAX(ID) AS max_id
  FROM games 
  GROUP BY name, code
) AS dt ON dt.name = g.name AND 
           dt.code = g.code AND 
           dt.max_id = g.ID 
WHERE g.name IN ('ACK1134', 'ACK1159')
  AND g.code IN ('CD23')
ORDER BY g.ID desc

MySQL查询-按日期和ID过滤

1 个答案: