从foreach php中删除重复项

Question

我已经尝试过array_unique，但是没有得到想要的结果。

这是数据库结构：

这是我尝试过的方法，但是两次获得相同的“用户1”应该是一个。

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以下是来自db的数据：

$stmt = $db_con->query("SELECT sender,recipient, content, sending_time
FROM messages AS sender
WHERE (sender='admin' OR recipient='admin')
GROUP BY sender,recipient
ORDER BY sending_time DESC
");

$stmt->execute();
foreach ($stmt as $key => $value) {

    if ($value['sender'] == 'admin') {
        $my = $value['recipient'];
    } else if ($value['recipient'] == 'admin') {
        $my = $value['sender'];
    } else {
        $my = $value['sender'];
    }
    if (!in_array($my, explode(' ', $my))) {
        echo '<a href="javascript:void(0)" class="list-group-item p10 b0 b-rad-0">
                    <div class="online-users pull-left mr5">
                        <img src="../uploads/userprofile/default/avatar.jpg" onerror="this.onerror=null;imgDefault(this);" alt="avatar" class="online-users-img">
                        <span title="online"></span>
                    </div>
                    <strong class="text-primary h4 mb2">' . $my . '<small class="pull-right">OCT 23</small></strong>
                    <div><small class="text-muted">asdasdajkasdhjgjhgjhgjhgjghjgjgggggggggggggsdfsdf...</small></div>
                </a>';

    }
}

Answer 1

//Find duplicates 

$arr_data = array( 
    'one', 
    'two', 
    'Three', 
    'Four', 
    'Five', 
    'Six', 
    'Seven', 
    'Eight', 
    'Nine' 
);
$unique_data = array_unique($arr_data); 
$dup= array_diff_key( $arr_data, $unique_data); 
array_count_values($dup);