Question

我有一个由字符串和另一个列表组成的元组列表；

[['string1a1', 'string1b1'],
 ['string2a2', 'string2b2'],
 ['string3a3', 'string3b3']]

我无法弄清楚使用列表理解来得出类似的结果；

results = [join(ministring, i) for i in (miniarray for (ministring, miniarray) in myarray)]

我尝试过类似的

Problem 1
    - Installation request for symfony/symfony v3.3.17 -> satisfiable by symfony/symfony[v3.3.17].
    - don't install symfony/var-dumper v4.0.12|don't install symfony/symfony v3.3.17
    - Installation request for symfony/var-dumper v4.0.12 -> satisfiable by symfony/var-dumper[v4.0.12].

但是我对扩展/表达式（？）中的每个变量范围感到困惑。

Answer 1

就这么简单：

{
    "103.46.233.22:83":
    {
        "allowed":["get","post","cookie","referer","user_agent"],
        "disallowed":[],
        "proxy_level":"transparent",
        "info":
        {
            "url":"http:\/\/test.com\/ping.php?q=query",
            "content_type":"text\/html; charset=UTF-8",
            "http_code":200,
            "header_size":385,
            "request_size":318,
            "filetime":-1,
            "ssl_verify_result":0,
            "redirect_count":0,
            "total_time":1.547,
            "namelookup_time":1.0e-6,
            "connect_time":0.328,
            "pretransfer_time":0.328,
            "size_upload":143,
            "size_download":127,
            "speed_download":82,
            "speed_upload":92,
            "download_content_length":-1,
            "upload_content_length":143,
            "starttransfer_time":0.328,
            "redirect_time":0,
            "redirect_url":"",
            "primary_ip":"103.46.233.22",
            "certinfo":[],
            "primary_port":83,
            "local_ip":"172.20.0.250",
            "local_port":52594
        }
    },
    "106.233.22.13:8080":
    {
        "allowed":["get","post","cookie","referer","user_agent"],
        "disallowed":[],
        "proxy_level":"transparent",
        "info":
        {
            "url":"http:\/\/test.com\/ping.php?q=query",
            "content_type":"text\/html; charset=UTF-8",
            "http_code":200,
            "header_size":385,
            "request_size":318,
            "filetime":-1,
            "ssl_verify_result":0,
            "redirect_count":0,
            "total_time":1.547,
            "namelookup_time":1.0e-6,
            "connect_time":0.328,
            "pretransfer_time":0.328,
            "size_upload":143,
            "size_download":127,
            "speed_download":82,
            "speed_upload":92,
            "download_content_length":-1,
            "upload_content_length":143,
            "starttransfer_time":0.328,
            "redirect_time":0,
            "redirect_url":"",
            "primary_ip":"106.233.22.13",
            "certinfo":[],
            "primary_port":8080,
            "local_ip":"172.20.0.250",
            "local_port":52594
        }
    }
}

返回：

lst = [('string1', ['a1', 'b1']),
 ('string2', ['a2', 'b2']),
 ('string3', ['a3', 'b3'])]

res = [[master + tail for tail in sublist] for master, sublist in lst]

请注意，采用这种方法时，元组内部子列表的长度是固定的。它可以任意长。

Answer 2

您可以执行以下操作：

data = [('string1', ['a1', 'b1']),
 ('string2', ['a2', 'b2']),
 ('string3', ['a3', 'b3'])]

result = [[s + e1, s + e2] for s, [e1, e2] in data]
print(result)

输出

[['string1a1', 'string1b1'], ['string2a2', 'string2b2'], ['string3a3', 'string3b3']]

请注意，这假设内部列表仅包含两个元素。

Answer 3

尝试一下：

new_list = list(map(lambda x: [x[0]+x[1][0], x[0]+x[1][1]],data))

列表理解中的可变范围

3 个答案: