swift 4.2如何以编程方式退出电话？

Question

使用另一个答案中的以下代码来检测电话状态，它可以正常工作，但是现在我需要创建一个func，在该函数中，以编程方式关闭电话10秒钟后， 或放置一个按钮以使用户关闭它。 甚至可以检测到用户按下红色按钮。

代码

//        CXCallController.request(transaction) { error in

便笺是否有效

立即测试：

func endCall(call: UUID) {

        let endCallAction = CXEndCallAction(call: call)
        let transaction = CXTransaction(action: endCallAction)
        let cxcontrolelr = CXCallController()
//        CXCallController.request(transaction) { error in
//            if let error = error {
//                print("EndCallAction transaction request failed: \(error.localizedDescription).")
//                self.cxCallProvider.reportCall(with: call, endedAt: Date(), reason: .remoteEnded)
//                return
//            }

        CXCallController.requestTransaction(cxcontrolelr)
            print("EndCallAction transaction request successful")

        }

    }


func closeTheCAll() {

        //            let myUuid = UIDevice.current.identifierForVendor?.uuidString
        let myUuid = UUID().uuidString
        print(myUuid)
        endCall(call: myUuid)

    }



 //MARK: Monitoring call status section //this is working with no issue
    func callObserver(_ callObserver: CXCallObserver, callChanged call: CXCall) {
        if call.hasEnded == true {
            print("Disconnected")

        }
        if call.isOutgoing == true && call.hasConnected == false {
            print("Dialing")
        }
        if call.isOutgoing == false && call.hasConnected == false && call.hasEnded == false {
            print("Incoming")
        }
        if call.hasConnected == true && call.hasEnded == false {
            print("Connected")

        }
    }