Question

我有下表及其活动时间的项目表（期间由FROM和TO日期定义）：

ID | ProjID | ActiveFrom | ActiveTo
===+========+============+============
 1 |     20 | 2018-01-01 | 2018-01-04
 2 |     20 | 2018-02-05 | 2018-02-07
 3 |     20 | 2018-02-20 | 2018-02-22
 4 |     30 | 2018-01-15 | 2018-02-15

项目有任意数量的活动周期。

我需要一个查询，该查询将返回给定项目的所有活动日期。例如对于ProjID = 20，结果应为：

Answer 1

您是这样说的吗？

SET @row_number = 0;
SELECT DATE_ADD(DATE_ADD(ActiveFrom, INTERVAL -1 DAY), INTERVAL x.D DAY) AS ActivityPeriods
FROM test
LEFT JOIN(SELECT *, (@row_number:=@row_number + 1) AS D  FROM information_schema.COLUMNS) AS x ON x.D <= DATEDIFF(ActiveTo,ActiveFrom) +1
WHERE 
    ProjID = 20
   ORDER BY ActivityPeriods

这会给你：

| ActivityPeriods |
| --------------- |
| 2018-01-01      |
| 2018-01-02      |
| 2018-01-03      |
| 2018-01-04      |
| 2018-02-05      |
| 2018-02-06      |
| 2018-02-07      |
| 2018-02-20      |
| 2018-02-21      |
| 2018-02-22      |

Fiddle Demo

列出一段时间内的所有日期

1 个答案: