正在从IMDb抓取电视剧集(在下面的示例中为Breaking Bad)。问题是在实现for
循环时,仅返回j
的第一次迭代。
我的假设是return语句正在退出循环,但是我不确定如何解决该问题。
const fetch = require('node-fetch');
const cheerio = require('cheerio');
const searchUrl = 'https://www.imdb.com/find?s=tt&ttype=tv&ref_=fn_tv&q=';
const movieUrl = 'https://www.imdb.com/title/';
async function getEpisodes(searchTerm) {
//const imdbID = await getID(searchTerm);
//const numSeasons = await getSeasons(imdbID);
const imdbID = 'tt0903747';
const numSeasons = 5;
const episodes = [];
for (let j = 1; j <= numSeasons; j++) {
return fetch(`${movieUrl}${imdbID}/episodes?season=${j}`)
.then(response => response.text())
.then(body => {
const $ = cheerio.load(body);
$('div[itemProp="episodes"]').each(function (i, element) {
const airdate = $(element).find('.airdate').text().trim();
const episodeTitle = $(element).find('a[itemProp="name"]').text().trim();
const votes = $(element).find('.ipl-rating-star__total-votes').text().trim().match(/\(([^)]+)\)/)[1];
const rating = $(element).find('.ipl-rating-star ').find('.ipl-rating-star__rating').text().trim().slice(0, 3);
episode = {
season: j,
episodeTitle,
airdate,
votes,
rating
};
episodes.push(episode);
});
return episodes; //Only season 1 is returned.
});
}
}
答案 0 :(得分:0)
让我们使用异步等待样式重写函数。这样,我们可以确保fetch
numSeasons
次触发,等待所有它们,然后一个接一个地处理它们。
async function processResponse(response, season) {
const body = await response.text();
const $ = cheerio.load(body);
let episodes = [];
$('div[itemProp="episodes"]').each(function (i, element) {
const airdate = $(element).find('.airdate').text().trim();
const episodeTitle = $(element).find('a[itemProp="name"]').text().trim();
const votes = $(element).find('.ipl-rating-star__total-votes').text().trim().match(/\(([^)]+)\)/)[1];
const rating = $(element).find('.ipl-rating-star ').find('.ipl-rating-star__rating').text().trim().slice(0, 3);
episode = {
season,
episodeTitle,
airdate,
votes,
rating
};
episodes.push(episode);
});
return episodes;
}
async function getEpisodes(searchTerm) {
//const imdbID = await getID(searchTerm);
//const numSeasons = await getSeasons(imdbID);
const imdbID = 'tt0903747';
const numSeasons = 5;
let promises = [];
for (let j = 1; j <= numSeasons; j++) {
promises.push(fetch(`${movieUrl}${imdbID}/episodes?season=${j}`));
}
const responses = await Promise.all(promises);
return responses.reduce((accumulator, response, index) => {
return accumulator.concat(await processResponse(response, index + 1));
}, []);
}