Question

我如何根据下面给出的数据列表使用while循环返回3个最大值：

list_of_numbers = [
                   ['A',12.0],
                   ['B',52.0],
                   ['C',5.5],
                   ['D',77.0],
                   ['E',55.0],
                   ['F',3.7,]
                  ]

所需的输出：

[ 
  ['D',77.0],
  ['E',55.0],
  ['B',52.0]

]

Answer 1

In [9]: list_of_numbers = [
   ...:     ['A', 12.0],
   ...:     ['B', 52.0],
   ...:     ['C', 5.5],
   ...:     ['D', 77.0],
   ...:     ['E', 55.0],
   ...:     ['F', 3.7]
   ...: ]

In [10]: sorted(list_of_numbers, key=lambda x: x[1], reverse=True)[:3]
Out[10]: [['D', 77.0], ['E', 55.0], ['B', 52.0]]

key=lambda x: x[1]意味着按照所有这些列表的第二个元素对其进行排序

reverse=True按降序排列

[:3]是一个切片，它从已排序的列表中获取元素0、1和2，因此前三名

使用While循环返回3个最大值

1 个答案: