一个关于弹簧靴大师的问题!
用例:
我希望我的应用程序的行为取决于以下路由:
render
通过作为URL参数发送的json网络令牌(jwt)进行授权(我知道,这很奇怪)jwt的秘密存储为应用程序配置(application.yaml)的元素(我知道这不是最佳实践,因为它是演示应用程序,所以我不在乎)
我正在使用SpringBoot 2.0.5
和io.jsonwebtoken
作为jwt库。
我已经使用Servlet过滤器实现了它,并且可以正常工作,但是感觉真的很丑。我找不到说“ 将此Servlet过滤器应用于除此列表以外的所有端点”的方法。我已经将逻辑包含在doFilter方法中,但是这个看起来确实很丑。
这是否有“最佳实践”?
我当前的代码如下:
SecurityConfiguration
import org.springframework.context.annotation.Configuration;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
@Configuration
public class SecurityConfiguration extends WebSecurityConfigurerAdapter {
@Override
protected void configure(HttpSecurity httpSecurity) throws Exception {
httpSecurity.authorizeRequests()
.antMatchers("/").permitAll()
.antMatchers("/render").permitAll()
.anyRequest().authenticated();
httpSecurity.headers().frameOptions().disable();
}
}
WebConfigurer
import org.springframework.boot.web.servlet.ServletContextInitializer;
import org.springframework.context.annotation.Configuration;
import javax.servlet.DispatcherType;
import javax.servlet.FilterRegistration;
import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import java.util.EnumSet;
@Configuration
public class WebConfigurer implements ServletContextInitializer {
@Override
public void onStartup(ServletContext servletContext) throws ServletException {
EnumSet<DispatcherType> disps = EnumSet.of(DispatcherType.REQUEST, DispatcherType.FORWARD, DispatcherType.ASYNC);
initFilter(servletContext, disps);
}
private void initFilter(ServletContext servletContext,
EnumSet<DispatcherType> disps) {
FilterRegistration.Dynamic myFilter =
servletContext.addFilter("myFilter",
new JWTAuthenticationFilter());
myFilter.addMappingForUrlPatterns(disps, true, "/app/*");
myFilter.setAsyncSupported(true);
}
}
JWTAuthenticationFilter
import io.jsonwebtoken.Claims;
import io.jsonwebtoken.Jws;
import io.jsonwebtoken.Jwts;
import io.jsonwebtoken.impl.TextCodec;
import org.springframework.beans.factory.annotation.Value;
import org.springframework.security.core.context.SecurityContextHolder;
import org.springframework.stereotype.Component;
import org.springframework.web.filter.GenericFilterBean;
import javax.servlet.FilterChain;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
@Component
public class JWTAuthenticationFilter extends GenericFilterBean {
@Value("${security.jwt.token.secret-key}")
private String secret;
@Override
public void doFilter(ServletRequest req,
ServletResponse res,
FilterChain filterChain) throws IOException, ServletException {
HttpServletRequest request = (HttpServletRequest) req;
HttpServletResponse response = (HttpServletResponse) res;
try {
String path = request.getRequestURI();
if (!path.equals("/")) {
String jwsString = request.getParameter("jwt");
Jws<Claims> jws;
String base64_encoded_secret = TextCodec.BASE64.encode(secret);
jws = Jwts.parser()
.setSigningKey(base64_encoded_secret)
.parseClaimsJws(jwsString);
}
} catch (Exception e) {
System.out.println(e);
response.sendError(HttpServletResponse.SC_UNAUTHORIZED, "Authentication failed");
SecurityContextHolder.clearContext();
}
filterChain.doFilter(request, response);
}
}
答案 0 :(得分:0)
找到了解决方案!我使用了FilterRegistrationBean。无法排除URL。我的解决方案是将所有应用程序放在app /目录下,因此我不需要在根目录/上放置过滤器。
@Bean
public FilterRegistrationBean FilterRegistration() {
FilterRegistrationBean registration = new FilterRegistrationBean();
registration.setFilter(filter);
registration.setOrder(1);
registration.addUrlPatterns("/app/*");
return registration;
}