Question

我已经为Android应用程序提供了一些扩展代码。

主要活动具有一个展示有Button的FrameLayout。该按钮的背景是可绘制（XML）。

==> resources / layout / Layout.axml

<FrameLayout xmlns:android="http://schemas.android.com/apk/res/android"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:background="#999999">
    .../...
     <Button
            android:id="@+id/the_button"
            android:layout_width="70dp"
            android:layout_height="70dp"
            android:layout_gravity="center_horizontal|bottom"
            android:layout_marginBottom="40dp"
            android:gravity="center_vertical|center_horizontal"
            android:background="@drawable/btn" />
    </FrameLayout>

该按钮使用可绘制对象使其具有边框。

==> resources / drawable / btn.xml

<selector xmlns:android="http://schemas.android.com/apk/res/android">
  <item android:state_pressed="false">
    <shape android:shape="oval">
      <solid android:color="#20000000"/>
      <stroke android:width="2dp" android:color="#000000"/>
      <size android:width="60dp" android:height="50dp" />
    </shape>
  </item>
  <item android:state_pressed="true">
    <shape android:shape="oval">
      <solid android:color="#FF000000"/>
      <stroke android:width="2dp" android:color="#000000"/>
      <size android:width="60dp" android:height="50dp" />
    </shape>
  </item>
</selector>

在应用程序生命周期的某一时刻，按钮的边框（上面的笔触）应更改颜色。如何更改上面的笔触颜色？使用常规的FindViewById<Button>(Resource.Id.the_button)无济于事。

谢谢。

解决方案-Th。G.hakim

Button _theButton = FindViewById<Button>(Resource.Id.the_button);
GradientDrawable _stroke = (GradientDrawable)_theButton.Background.Current;
_stroke.SetStroke(2, Color.Red);

Answer 1

我会这样做：

import {
  Component,
  OnInit,
  Input,
  Output,
  EventEmitter
} from '@angular/core';
import {
  MatStepper
} from '@angular/material';
import {
  FormGroup,
  FormBuilder
} from '@angular/forms';



@Component({
  selector: 'cby-step',
  templateUrl: './cby-step.component.html',
  styleUrls: ['./cby-step.component.scss']
})
export class CbyStepComponent implements OnInit {
  @Input() stepper: MatStepper;
  public childForm: FormGroup;
  constructor(private fb: FormBuilder) {}

  ngOnInit() {
    this.childForm = this.fb.group({
      id: [0, '']
    });
  }

  previous() {
    this.updateForm();
    this.stepper.previous();
  }

  next() {
    this.updateForm();
    this.stepper.next();
  }

  updateForm() {
    this.childForm.controls['id'].setValue(this.stepper.selectedIndex);
    console.log(this.childForm.controls['id'].value);
  }

}

从代码（xamarin.android）更改可绘制对象的颜色

1 个答案: