Question

我正在尝试编写一个 Hill-RSA 加密程序，您可以在此处看到部分内容：

q2=31
alphabet=["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z",","," ",".",";","_"]
X=np.zeros((m,1),dtype=np.int32)
Y=np.zeros((m,1),dtype=np.int32)
Texte_decode="";
for i in range(1,(len(Texte_code)/m)+1):
    for k in range(0,m):
        j=0
        while (Texte_code[k+m*(i-1)]<>alphabet[j+1]):
            j=j+1
        X[k]=j
    X=X.transpose()
    A2=np.zeros((m,m),dtype=np.int32)
    for u in range(0,m):
        for l in range(0,m):
            A2[u,l]=A[u,l]
    Y=X.dot(A2)
    Y=Y.transpose()
    pprint(Y)
    Y2=np.zeros((m,1),dtype=np.int32)
    for ind in range(0,m):
        Y2[ind]=Y[ind]%q2
    pprint(Y2)
    for k in range(0,m):
        Texte_decode=Texte_decode+alphabet[Y2[k]+1]
for i in range(len(Texte_decode),len(Texte_decode)-m+1,-1):
    if Texte_decode[i]=="." and Texte_decode[i-1]==".":
        Texte_decode=Texte_decode[1,i-1]
print Texte_decode

执行此部分时，我得到

“ TypeError：只有整数标量数组可以转换为标量索引”

在线

Texte_decode=Texte_decode+alphabet[Y2[k]+1]

有人可以帮我摆脱这个错误吗？

预先感谢

Answer 1

您完成了哪些调试？您是否审查了问题专线元素的性质？

Texte_decode=Texte_decode+alphabet[Y2[k]+1]

k来自for k in range(0,m):，所以这不是问题。显然是整数。

您打印的Y2。它初始化为(m,1)数组。所以Y2[k]将是（1，）数组，对吧？

alphabet是一个列表。

在交互式外壳中，让我们尝试一个测试用例：

In [70]: [1,2,3,4][np.array([1])]
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-70-4ad73b219fa3> in <module>()
----> 1 [1,2,3,4][np.array([1])]

TypeError: only integer scalar arrays can be converted to a scalar index

相同的错误消息！

如果我们从一维数组开始，然后选择一个元素，则索引将起作用：

In [71]: [1,2,3,4][np.arange(4)[1]]
Out[71]: 2

现在我们了解了问题，解决方案应该很明显，对吧？

Hill-RSA密码学中的“ TypeError：仅整数标量数组可以转换为标量索引”

1 个答案: