Question

我输入的内容会有所不同。

data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]

寻找按键[0]分组的输出，保留键[1]的所有项目。并且，对这些值求和。

output = [(("101", "A", "B"),9), (("105", "C"),12)]

我已经尝试过了。

my_dict = dict(data)
final_values = {}
for k,v in my_dict.items():
    key1 = k[0]
    key2 = k[1]

    if key1 not in final_values:
        final_values[key1] = []
    final_values[key1].append(key2)
    final_values[key1].append(v)

哪个回来。

{'101': ['A', 5, 'B', 4], '105': ['C', 12]}

我想获取列表中数字的总和。

Answer 1

while True:
    container = driver.find_elements_by_xpath('.//*[contains(@class,"review-container")]')
    for items in container:
        element = WebDriverWait(driver, 1000).until(EC.element_to_be_clickable((By.XPATH,'.//*[contains(@class,"taLnk ulBlueLinks")]')))
        element.click()
        time.sleep(10)
        contained = items.find_elements_by_xpath('.//*[contains(@class,"ui_column is-9")]')
        for item in contained:
            try:
                driver.execute_script("[...document.querySelectorAll('.mgrRspnInLine')].map(el => el.parentNode.removeChild(el))")
                rating = item.find_element_by_xpath('//*[contains(@class,"ui_bubble_rating bubble_")]')
                rate = rating .get_attribute("class")
                rate = str(rate)
                rate = rate[-2:]
                score_list.append(rate)
                time.sleep(2)
                stay = item.find_element_by_xpath('.//*[contains(@class,"recommend-titleInline")]')
                stayed = stay.text
                stayed = stayed.split(', ')
                stayed.append(stayed[0])
                travel_type.append(stayed[1])
                WebDriverWait(driver, 50).until(EC.presence_of_element_located((By.XPATH,'.//*[contains(@class,"noQuotes")]')))
                summary = item.find_element_by_xpath('.//*[contains(@class,"noQuotes")]')
                comment = summary.text
                comments.append(comment)
                WebDriverWait(driver, 50).until(EC.presence_of_element_located((By.XPATH,'.//*[contains(@class,"ratingDate")]')))
                rating_date = item.find_element_by_xpath('.//*[contains(@class,"ratingDate")]')
                date = rating_date.get_attribute("title")
                date = str(date)
                review_date.append(date)
                WebDriverWait(driver, 50).until(EC.presence_of_element_located((By.XPATH,'.//*[contains(@class,"partial_entry")]')))
                review = item.find_element_by_css_selector(".partial_entry")
                comment = review.text
                print(comment)
            except (NoSuchElementException) as e:
                continue
    try:
        element = WebDriverWait(driver, 100).until(EC.element_to_be_clickable((By.XPATH,'.//*[contains(@class,"nav next taLnk ui_button primary")]')))
        element.click()
        time.sleep(2)
    except (ElementClickInterceptedException,NoSuchElementException) as e:
        print(e)
        break

Answer 2

您可以尝试使用collections.defaultdict()对项目进行分组，然后在末尾将结果展平：

from collections import defaultdict
from operator import itemgetter

data = [(("101","A"),5), (("105","C"),12), (("101", "B"),4)]

d = defaultdict(list)
for (x, y), z in data:
    d[x].append((y, z))

result = [
    ((k, *tuple(map(itemgetter(0), v))), sum(map(itemgetter(1), v)))
    for k, v in d.items()
]
print(result)
# [(('101', 'A', 'B'), 9), (('105', 'C'), 12)]

Python减少和元组

2 个答案: