Question

嗨，我正在学习python，在一次练习中，他们问我一个函数，该函数接受任意数量的参数，并返回仅包含偶数个参数的列表。

我知道我的代码是错误的

def myfunc(*args):
    for n in args:
        if n%2 == 0:
            return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)

Answer 1

执行列表理解，从number_of_payments中选择与我们的选择条件匹配的元素：

args

Answer 2

这也可能会有所帮助，但是，前面的注释看起来更高级：

def myfunc(*args):
    lista = []
    for i in list(args):
        if not i % 2:
            lista.append(i)
    return lista

Answer 3

连拍

def myfunc(*args):
    abc = []
    for n in args:
        if n%2==0:
            abc.append(n) 
    return abc

Answer 4

def myfunc(*args):
    mylist = []
    for x in list(args):
        if x % 2 == 0:
            mylist.remove(x)
    return mylist

Answer 5

def myfunc(*args):
    even=[]
    for n in args:
        if n %2==0:
            even.append(n)
        else:
            pass
        
    return even
myfunc(1,2,3,4,8,9)

Answer 6

def myfunc(*args):
    #solution 1
    # Create an empty list
    mylist = []
    for number in args:
        if number %2 == 0:
            mylist.append(number)
        else:
            pass
    # return the list
    return mylist
    
    #solution 2
    # Uses a list comprehension that includes the logic to find all evens and the list comprehension returns a list of those values
    # return [n for n in args if n%2 == 0]

Answer 7

您需要创建一个空列表来包含偶数。还将您的参数转换为列表。然后将偶数附加到新创建的列表中。

def myfunc(*args):
new_list = []
for num in list(args):
    if num % 2 == 0:
        new_list.append(num)
else:
    pass
return new_list

Answer 8

def myfunc(*args):
    x=[]
    for i in list(args):
        if i%2==0:
            x.append(i)
    return x

* args返回仅包含偶数（PYTHON）参数的列表

8 个答案: