Question

我试图用另一个提供ID的表中的某些列填充一个表，但出现此错误：

1064-您的SQL语法有错误；检查与您的MariaDB服务器版本相对应的手册以获取在'type of products.CategoryID'中使用正确的语法。 DECLARE t_productid产品的类型。ProductID；'在第4行

我不知道如何解决它，希望您能为我提供帮助。

 DELIMITER //
 Create procedure getProducts(v_categoryid int)
 BEGIN
    DECLARE done INT DEFAULT FALSE;
    DECLARE t_categoryid type of products.CategoryID;
    DECLARE t_productid type of products.ProductID;
    DECLARE t_productname type of products.ProductName;
    DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
    DECLARE cur1 CURSOR(p_categoryid int)
    FOR
    SELECT CategoryID, ProductID, ProductName 
    FROM products
    WHERE CategoryID = p_categoryid; 

    create table IF NOT exists curProducts(
    CategoryID int(10),
    ProductID int(10),
    ProductName varchar(40));

    truncate table curProducts;
    open cur1(v_categoryid);
    read_loop: LOOP
       FETCH cur1 INTO t_categoryid, t_productid, t_productname;
       IF done THEN
          LEAVE read_loop;
       END IF;
       INSERT INTO curProducts VALUES (t_categoryid, t_productid, t_productname);
    END LOOP;
    close cur1;

    select * from curProducts;
END // 
DELIMITER ;

Answer 1

您可以使用显式类型，也可以升级到引入了TYPE OF语法的mariadb-10.3。

Answer 2

此解决方案通过不需要这些语句来避免语法错误！

DECLARE done INT DEFAULT FALSE;
DECLARE t_categoryid type of products.CategoryID;
DECLARE t_productid type of products.ProductID;
DECLARE t_productname type of products.ProductName;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
DECLARE cur1 CURSOR(p_categoryid int)
FOR
SELECT CategoryID, ProductID, ProductName 
FROM products
WHERE CategoryID = p_categoryid; 

open cur1(v_categoryid);
read_loop: LOOP
   FETCH cur1 INTO t_categoryid, t_productid, t_productname;
   IF done THEN
      LEAVE read_loop;
   END IF;
   INSERT INTO curProducts VALUES (t_categoryid, t_productid, t_productname);
END LOOP;
close cur1;

所有这些都可以替换为

INSERT INTO curProducts VALUES (t_categoryid, t_productid, t_productname)
    SELECT CategoryID, ProductID, ProductName 
    FROM products
    WHERE CategoryID = p_categoryid;

声明mariaDB错误。如何解决此查询？

2 个答案: