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这是我拥有的代码，我很傻，很可能会错过一个非常基本的错误。它在scanf行上发生段错误。我该如何解决这个问题？

Answer 1

分段错误不是在scanf处，而是在printf处。正如@TypeIA在注释部分中提到的，这是因为printf期望有一个指向格式字符串的指针，而不是整数本身。为此，就像在使用%d接受整数作为输入时使用格式说明符scanf一样，在使用printf打印时也需要使用相同的格式，即

printf("%d",n);请注意%d之前的n。

更新的代码：

#include <stdio.h>

int main() {
    int n;
    scanf("%d", &n);
    printf("%d",n);
    return 0;
}

Answer 2

像下面这样使用printf()：

printf("%d", n);

在使用code之前，您可能在scanf中犯了一个错误。例如，如果您在未初始化的数组中复制一个指向内存中无处的字符串，则可能会发生这种情况。

scanf在scanf的行上产生段错误

2 个答案: