Question

我使用remix IDE。当我调用该函数获取编号时，得到了0：uint256 []：
如何更改它以返回动态数组的数字？

实用性^ 0.4.24;

contract dynamicarray { 

    uint public constant MaxNumber = 50;

    uint[] numbers;

    function randomnumber() public view returns (uint){
        uint random = uint(sha3(block.timestamp)) % MaxNumber +1;
        for(uint i = MaxNumber; i > numbers.length; i++){
            numbers.push(random);  
            return  random;
        }
    }

    function getnumbers() public view returns(uint[]){
        return  numbers;
    }
}

Answer 1

该函数是view，因此它不能修改状态。调用randomnumber()将返回一个值，但不会更改numbers数组。

从view中删除randomnumber()修饰符，它将在数组中添加一项。（提早返回将防止循环重复。）

Answer 2

尝试一下

pragma solidity ^0.4.24;

contract dynamicarray { 

    uint public constant MaxNumber = 50;

    uint[] numbers;

    function randomnumber() public returns (uint){
        uint random = uint(keccak256(block.timestamp)) % MaxNumber +1;
        for(uint i = MaxNumber; i > numbers.length; i++){
            numbers.push(random);  
            return  random;
        }
    }

    function getnumbers() public view returns(uint[]){
        return  numbers;
    }
}

可靠性-将随机数存储到动态数组中并返回该数组

2 个答案: