Question

我知道这个问题已经被问过很多次了，但是我根本无法理解我做错了什么。每当我取得一些进展时，我都会收到一个新错误。我使用的代码非常基础，因为我是新手，我们的教授要求使用scanf并获取。到目前为止，这是我的代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_SIZE 100
int identify(char[], char[]);
int remove(char[], char[], int);
int scan(choice)
{
    while(choice < 0 || choice > 7)
    {
        printf("Invalid input, choose again\n");    
        scanf("%d", &choice);
    }
    return choice;  
}


int main()
{
    char sentence[MAX_SIZE], word[MAX_SIZE];
    int choice, i, j, k, deikths;

    printf("Choose one of the following:\n");
    printf("1. Give sentence\n");
    printf("2. Subtract a word\n");
    printf("3. Add a word\n");
    printf("4. Count the words\n");
    printf("5. Count the sentences\n");
    printf("6. Count the characters\n");
    printf("7. Is the phrase a palindrome?\n");
    printf("0. Exit\n");
    scanf("%d", &choice);
    if(scan(choice) == 1)
    {
        printf("Give sentence:\n");
        gets(sentence);
        gets(sentence);
        printf("%s\n", sentence);
    }
    else(scan(choice) == 2);
    {
        printf("Give word you want to subtract\n");
        gets(word); 
        printf("%s", word);
        deikths = identify(sentence, word);
        if(deikths != -1)
        {
            remove(sentence, word, deikths);
            printf("Sentence without word: %s\n", sentence);
        } 
        else
        {
            printf("Word not found in sentence.\n");
        }
    }
}

int identify(char sentence[], char word[])
{
    int i, j, k;
    for(k = 0; word[k] != '\0'; k++);
    {
        for(i = 0, j = 0; sentence[i] != '\0'; i++)
        {
            if(sentence[i] == word[j])
            {
                j++;
            }
            else
            {
                j = 0;
            }
        }
    }
    if(j == 1)
    {
        return(i - j);
    }
    else
    {
        return -1;
    }
}

int remove(char sentence[], char word[], int deikths)
{
    int i, k;
    for(k = 0; word[k] != '\0'; k++)
    {
        for(i = deikths; sentence[i] != '\0'; i++)
        {
            sentence[i] = sentence[i + k + 1];
        }       
    }
}

我得到的错误是remove函数的类型冲突。修复我的代码的任何帮助将不胜感激，甚至可以替代解决我的问题的方法。

Answer 1

如注释中所述，由于width中已经定义了remove，因此会生成编译器错误。更改后，代码名称可以成功编译，但仍无法按预期工作。

stdio.h是用于查找字符串中是否存在子字符串并返回其位置的函数。这与标准库中的identify的工作原理非常相似-我建议您看一下该函数的实现，以更好地了解其实现方式。您仅实现的函数只能在字符串末尾找到长度为1的子字符串。我在下面的代码中突出显示了导致此错误的错误。

strstr

int identify(char sentence[], char word[]) { int i, j, k; for(k = 0; word[k] != '\0'; k++); // <- this loops is never actually ran because of the trailing semicolon - this is however a good thing as it is redundant { for(i = 0, j = 0; sentence[i] != '\0'; i++) { if(sentence[i] == word[j]) { j++; } else { j = 0; // <- this makes it so only matches at the end can be found - otherwise, j is just reset back to 0 } } } if(j == 1) // <- this makes it so only matches of length 1 can be found { return(i - j); // <- this is only correct if the match is at the end of the sentence } else { return -1; } }由于嵌套循环而效率低下，复制的字符范围需要缩短-现在，数据访问超出了数组末尾。

strremove

我将int strremove(char sentence[], char word[], int deikths) { int i, k; for(k = 0; word[k] != '\0'; k++) // <- this loop is redundant { for(i = deikths; sentence[i] != '\0'; i++) // <- you need to add range checking to make sure sentence[i+k+1] doesn't go beyond the end of the string { sentence[i] = sentence[i + k + 1]; } } }中的问题留给您作为练习，毕竟这是一项任务。

尝试从C中的字符串中删除子字符串，但仍失败

1 个答案: