Question

我与多对多关系有问题。这些表是：成分和营养价值。我创建了两个实体之间的关系表，其中有成分和营养价值的外键（形成复合键）以及一些属性。

JoinedNutrionalValueIngredient类

import lombok.Data;
import javax.persistence.*;
import javax.validation.constraints.NotNull;
import java.io.Serializable;

@Entity @Data
public class JoinedNutrionalValueIngredient implements Serializable {

    @EmbeddedId
    private NutrionalValueIngredientId id;

    @ManyToOne(fetch= FetchType.LAZY)
    @MapsId("ingredient_id")
    private Ingredient ingredient;

    @ManyToOne(fetch=FetchType.LAZY)
    @MapsId("nutrional_value_id")
    private NutrionalValue nutrionalValue;

    @NotNull
    String matrixUnit;
    @NotNull
    int value;
    @NotNull
    String valueType;
}

NutrionalValueIngredientId类

import javax.persistence.*;
import java.io.Serializable;
import java.util.Objects;

@Embeddable
@Getter
@Setter
public class NutrionalValueIngredientId implements Serializable{

    @Column(name = "ingredient_id")
     private Long ingredient_id;

    @Column(name = "nutrional_value_id")
     private Long nutrional_value_id;

    public NutrionalValueIngredientId() {

    }   

        public NutrionalValueIngredientId(Long ingredient, Long nutrionalValue){
            this.ingredient_id=ingredient;
            this.nutrional_value_id=nutrionalValue;
        }

        public boolean equals(Object o) {
            if (this == o) return true;

            if (o == null || getClass() != o.getClass())
                return false;

            NutrionalValueIngredientId that = (NutrionalValueIngredientId) o;
            return Objects.equals(ingredient_id, that.ingredient_id) &&
                    Objects.equals(nutrional_value_id, that.nutrional_value_id);
        }

        @Override
        public int hashCode() {
            return Objects.hash(ingredient_id, nutrional_value_id);
        }
    }

当我尝试在关系表中插入新字段时，出现此错误：

{
  "timestamp": 1542653896247,
  "status": 500,
  "error": "Internal Server Error",
  "message": "Could not set field value [1] value by reflection : [class com.whateat.reciper.model.NutrionalValueIngredientId.ingredient_id] setter of com.whateat.reciper.model.NutrionalValueIngredientId.ingredient_id; nested exception is org.hibernate.PropertyAccessException: Could not set field value [1] value by reflection : [class com.whateat.reciper.model.NutrionalValueIngredientId.ingredient_id] setter of com.whateat.reciper.model.NutrionalValueIngredientId.ingredient_id",
  "path": "/v1/joinedNutrionalValueIngredients"
}

PS。对不起，我的英语。

编辑：我添加了构造函数和注释@Getter和@Setter，但是我有相同的错误。

营养价值类

@Data
@Entity
public class NutrionalValue implements Serializable {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    @NotNull
    private String name;
    @NotNull
    private String unit;
    @NotNull
    private String source;

    @ManyToOne
    @NotNull
    @JoinColumn(name = "category_id")
    private NutrionalValueCategory category;

    @OneToMany(mappedBy = "nutrionalValue")
    private Set<JoinedNutrionalValueIngredient> joined = new HashSet<JoinedNutrionalValueIngredient>();

}

编辑：在Debopam回答后，出现了此错误。

{
  "timestamp": 1542657216244,
  "status": 500,
  "error": "Internal Server Error",
  "message": "null id generated for:class com.whateat.reciper.model.JoinedNutrionalValueIngredient; nested exception is org.hibernate.id.IdentifierGenerationException: null id generated for:class com.whateat.reciper.model.JoinedNutrionalValueIngredient",
  "path": "/v1/joinedNutrionalValueIngredients"
}

Answer 1

按如下所示更改变量名称

长的component_id到长的componentid nutrional_value_id到nutrionalvalueid

示例

  @Column(name = "ingredient_id")
  Long ingredient_id;

到

@Column(name = "ingredient_id")
Long ingredientid;

然后为所有字段生成getter设置程序。 Hibernate无法设置字段，因为没有公共获取者/设置者。

Answer 2

为id实体“ NutrionalValueIngredientId”设置值，然后尝试将其插入为“ JoinedNutrionalValueIngredient”的嵌入式ID。请参考以下示例：

package com.example;
import java.io.Serializable;
import javax.persistence.Column;
import javax.persistence.Embeddable;

@Embeddable
public class EmployeeId implements Serializable
{
private static final long serialVersionUID = 1L;
@Column(name = "EMP_ID")
private int empId;
@Column(name = "DEPARTMENT")
private String department;

public EmployeeId()
{
    super();
}
public EmployeeId(int empId, String department)
{
    super();
    this.empId = empId;
    this.department = department;
}

public int getEmpId()
{
    return empId;
}
public void setEmpId(int empId)
{
    this.empId = empId;
}
public String getDepartment()
{
    return department;
}
public void setDepartment(String department)
{
    this.department = department;
}
@Override
public int hashCode()
{
    final int prime = 31;
    int result = 1;
    result = prime * result + ((department == null) ? 0 : department.hashCode());
    result = prime * result + empId;
    return result;
}
@Override
public boolean equals(Object obj)
{
    if (this == obj)
        return true;
    if (obj == null)
        return false;
    if (getClass() != obj.getClass())
        return false;
    EmployeeId other = (EmployeeId) obj;
    if (department == null)
    {
        if (other.department != null)
            return false;
    } else if (!department.equals(other.department))
        return false;
    if (empId != other.empId)
        return false;
    return true;
}
 }

请参阅上面的嵌入式ID类（EmployeeId）。这是Employee类的主键。因此，我们需要在Id class（EmployeeId）中设置值，然后将该ID类注入到Employee作为主键。然后它将起作用。如果没有主键，则该值为null。

package com.example;
import java.io.Serializable;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
@Entity
public class Employee implements Serializable
{
private static final long serialVersionUID = 1L;
@EmbeddedId
EmployeeId id;
@Column(name="EMP_NAME")
private String empName;

public Employee()
{
    super();
}
public Employee(EmployeeId id, String empName)
{
    super();
    this.id = id;
    this.empName = empName;
}
public EmployeeId getId()
{
    return id;
}
public void setId(EmployeeId id)
{
    this.id = id;
}
public String getEmpName()
{
    return empName;
}
public void setEmpName(String empName)
{
    this.empName = empName;
}
}

为Id类和其他字段设置值，如下所示。

 //Create a new Employee object   
 Employee employee = new Employee();

 EmployeeId employeeId = new EmployeeId(1,"DailyNews");
 employee.setEmpName("CompositeKey");
 employee.setId(employeeId);

 session.save(employee);

Answer 3

检查您正在为嵌入式 ID 设置实例。我没有遇到这个错误。

我改了

@EmbeddedId
ProductUserId id;    

ProductUser(Integer productId, Integer UserId, Double rating){
    this.rating = rating
}

到

@EmbeddedId
ProductUserId id;    

ProductUser(Integer productId, Integer userId, Double rating){
    this.id = new ProductUserId(productId, userId);
    this.rating = rating
}

Answer 4

 @Entity @Data
 public class JoinedNutrionalValueIngredient implements Serializable {
    
        @EmbeddedId
        private NutrionalValueIngredientId id = new NutrionalValueIngredientId();
    
    // ... rest of class  
 }

在 JoinedNutrionalValueIngredient 类中，复合 ID NutrionalValueIngredientId 应被实例化。

无法通过反射设置字段值

4 个答案: