我有HTML代码:
<div>
<h1>Header</h1>
<code><p>First code</p></code>
<p>Next example</p>
<code><b>Second example</b></code>
</div>
使用PHP,我想替换位于<
元素中的所有code
符号,例如上面要转换为的代码:
<div>
<h1>Header</h1>
<code><p>First code</p></code>
<p>Next example</p>
<code><b>Second example</b></code>
</div>
我尝试使用PHP DomDocument
类,但是我的工作效果不佳。下面是我的代码:
$dom = new DOMDocument();
$dom->loadHTML($content);
$innerHTML= '';
$tmp = '';
if(count($dom->getElementsByTagName('*'))){
foreach ($dom->getElementsByTagName('*') as $child) {
if($child->tagName == 'code'){
$tmp = $child->ownerDocument->saveXML( $child);
$innerHTML .= htmlentities($tmp);
}
else{
$innerHTML .= $child->ownerDocument->saveXML($child);
}
}
}
答案 0 :(得分:0)
因此,您正在正确地迭代标记,并且saveXML()
的使用接近了您想要的,但是您在代码中没有尝试实际更改元素的内容。这应该起作用:
<?php
$content='<div>
<h1>Header</h1>
<code><p>First code</p></code>
<p>Next example</p>
<code><b>Second example</b></code>
</div>';
$dom = new DOMDocument();
$dom->loadHTML($content, LIBXML_HTML_NODEFDTD | LIBXML_HTML_NOIMPLIED);
foreach ($dom->getElementsByTagName('code') as $child) {
// get the markup of the children
$html = implode(array_map([$child->ownerDocument,"saveHTML"], iterator_to_array($child->childNodes)));
// create a node from the string
$text = $dom->createTextNode($html);
// remove existing child nodes
foreach ($child->childNodes as $node) {
$child->removeChild($node);
}
// append the new text node - escaping is done automatically
$child->appendChild($text);
}
echo $dom->saveHTML();