如何使此代码打印数组中的最高值？

Question

如何制作此代码以打印数组中的最高值？

示例（view detailled screenshot）：

• 玩家1得分= 1
• 玩家2得分= 2

• 玩家3得分= 1

    

  玩家2是赢家。

• 玩家1得分= 1

• 玩家2得分= 3

• 玩家3得分= 3

    

  玩家2是赢家。
    玩家3是赢家。

• 玩家1得分= 1

• 玩家2得分= 1
• 玩家3得分= 1

    

  玩家1是赢家。
    玩家2是赢家。
    玩家3是获胜者。`

到目前为止，这是我尝试编写的代码：

/**
 * [algorithm description here]
 * @param players
 * @param cards
 */
public static void playGame(int players, int cards) {
    if (players * cards > 52) {
        System.out.println("Not enough cards for that many players.");
        return;
    }
    boolean[] deck = new boolean[52];
    int[] playerScore = new int[players];
    for (int i = 0; i < players; i++) {
        System.out.println("Player " + (i + 1));
        int[] hand = Cards.dealHandFromDeck(cards, deck);
        Cards.printHand(hand);
        System.out.println("Score = " + Cards.pointValue(hand));
        System.out.println();
        playerScore[i] = Cards.pointValue(hand);
    }
    //go through playerScore array twice, first to find the highest score, then who has that score
}

Answer 1

迭代playerScore，将其值与最大值进行比较，直到前一次迭代为止；如果迭代为零，则返回0。如果更大，则最大值为迭代值。

int maximumValue = 0;
for(int i = 0; i < playerScore.length; i++) {
    if(playerScore[i] > maximumValue) {
        maximumValue = playerScore[i];
    }
}

要检查播放器的最大值，可以使用与以前相同的代码段：

int maximumValue = 0;
long player = -1;
for(int i = 0; i < playerScore.length; i++) {
    if(playerScore[i] > maximumValue) {
        maximumValue = playerScore[i];
        player = i;
    }
}
if(player > -1) System.out.println("Player with highest score: " + (player + 1));