我具有要检测的此函数是value是否为整数。现在,当我输入十进制数字时,我在为数字设置的验证中会出错,我该如何放置 5.79 之类的值。它仅适用于整数
这是检查整数的功能
static isInt(value: any) {
var x: any;
return typeof value =="number";
}
我使用此验证来检查输入值是否为数字
static checkNumber(value: number, minNumber: number, maxNumber: number): IValdationResuslt {
if (value >= minNumber) {
if (value <= maxNumber) {
return { state: true, message: `Valid` } as Valid;
}
return { state: false, message: `Max Characters ${maxNumber} : Entered ${value}` } as IValdationResuslt;
}
return { state: false, message: `Min Number ${minNumber} : Entered ${value}` } as Invalid;
}
这是数字的输入验证检查
static inputValidation(value: any, state: any) {
switch (state.type) {
case "number":
//check if the value is a valid number
if (this.isInt(value)) {
//check if the minNumber value hase been exceeded
return this.checkNumber(value, state.minNumber, state.maxNumber);
}
return {
state: false,
message: "The value entered is not a number"
}
as IValdationResuslt;
case "telephone":
//check if the max length value has been exceeded
if (this.isInt(value)) {
//check if the minNumber value hase been exceeded
return this.checkNumber(value, state.minNumber, state.maxNumber);
}
}
}
答案 0 :(得分:2)
您可以使用Number.isFinite()
来评估输入是否为数字
const isNumber = (number) => Number.isFinite(number);
let num = 4;
console.log(`${num} is a number: ${isNumber(num)}`);
num = 4.54;
console.log(`${num} is a number: ${isNumber(num)}`);
num = 'a';
console.log(`${num} is a number: ${isNumber(num)}`);
// 4 is a number: true
// 4.54 is a number: true
// a is a number: false
答案 1 :(得分:1)
javascript的Number对象中已经有一个名为isInteger
的函数。
如果要检查值是否是数字而不是整数,则只需检查以下内容即可:
!Number.isInteger(value) && typeof value == "number"
答案 2 :(得分:0)
当我将其解析为float时,错误消失了。尽管我将其设置为数字形式,但仍被视为字符串。这样可以节省情况。
static isInt(value: any)
{
var check = parseFloat(value)
console.log(typeof check)
return check
}