Question

嗨，我在遍历javascript对象时遇到困难。如何从两者中获取scheme_name和NAV并将其存储在变量中，例如“您有2个与帐户关联的方案。scheme_name1 NAV值为“” scheme_name2 NAV值为“”，依此类推。请向我解释一下thanx

  let data = [{
  "CustomerID": 12345,
  "NAV": "95.24059718",
  "cost_of_purchase": 799900,
  "folio_number": 10007060,
  "id": 1,
  "mutual_fund_house": "AXIS MUTUAL FUND",
  "no_of_units": 15000,
  "option": "GROWTH",
  "plan": "REGULAR",
  "resource_uri": "/api/v1/folio/1/",
  "scheme_name": "AXIS LONG TERM EQUITY",
  "value_of_units": "1428608.9580"
}, {
  "CustomerID": 12345,
  "NAV": "1053.31517400",
  "cost_of_purchase": 1500000,
  "folio_number": 5540000567,
  "id": 2,
  "mutual_fund_house": "SBI Mutual Fund",
  "no_of_units": 2750,
  "option": "DIVIDEND",
  "plan": "DIRECT",
  "resource_uri": "/api/v1/folio/2/",
  "scheme_name": "SBI Magnum Multicap Fund",
  "value_of_units": "2896616.7270"
}]

Answer 1

您有一个data数组，因此首先需要遍历该数组。

选择每个记录要保留的属性，并将其保存到results数组中。

一旦获得结果，就可以遍历结果并打印出个人记录。

let data = [{"CustomerID":12345,"NAV":"95.24059718","cost_of_purchase":799900,"folio_number":10007060,"id":1,"mutual_fund_house":"AXIS MUTUAL FUND","no_of_units":15000,"option":"GROWTH","plan":"REGULAR","resource_uri":"/api/v1/folio/1/","scheme_name":"AXIS LONG TERM EQUITY","value_of_units":"1428608.9580"},{"CustomerID":12345,"NAV":"1053.31517400","cost_of_purchase":1500000,"folio_number":5540000567,"id":2,"mutual_fund_house":"SBI Mutual Fund","no_of_units":2750,"option":"DIVIDEND","plan":"DIRECT","resource_uri":"/api/v1/folio/2/","scheme_name":"SBI Magnum Multicap Fund","value_of_units":"2896616.7270"}]

let results = []
data.forEach(datum => {
  results.push({
    scheme_name: datum.scheme_name,
    nav: datum.NAV,
  })
})

console.log(`You've got ${results.length} items in your account.`)
results.forEach(result => {
  console.log(`${result.scheme_name} - NAV value is: ${result.nav}`)
})

Answer 2

想象一下您的每个对象（在本例中，您提供了两（2）个）作为数组内部的关联数组。意味着您可以通过键来引用它，而不是通过它的索引位置来引用它。

这意味着要访问对象1，您将必须写入数据[0]。但是，如果您对此发出警告，则只会告诉您data [0]是一个对象。是。

要访问该数组中的实际值，则必须提供键，您可以通过提供数字来完成，或者在您的情况下，更容易的是，它是关联的键，即“ scheme_name”。

请参阅以下内容：

let data = [{
  "CustomerID": 12345,
  "NAV": "95.24059718",
  "cost_of_purchase": 799900,
  "folio_number": 10007060,
  "id": 1,
  "mutual_fund_house": "AXIS MUTUAL FUND",
  "no_of_units": 15000,
  "option": "GROWTH",
  "plan": "REGULAR",
  "resource_uri": "/api/v1/folio/1/",
  "scheme_name": "AXIS LONG TERM EQUITY",
  "value_of_units": "1428608.9580"
}, {
  "CustomerID": 12345,
  "NAV": "1053.31517400",
  "cost_of_purchase": 1500000,
  "folio_number": 5540000567,
  "id": 2,
  "mutual_fund_house": "SBI Mutual Fund",
  "no_of_units": 2750,
  "option": "DIVIDEND",
  "plan": "DIRECT",
  "resource_uri": "/api/v1/folio/2/",
  "scheme_name": "SBI Magnum Multicap Fund",
  "value_of_units": "2896616.7270"
}]

for (let i = 0; i < data.length; i++) {
  alert(data[i]["scheme_name"]);
}

非常简单，对于i = 0，且i小于您名为data的数组中的关联数组的数量，请通过关联的键来提醒该索引数组上的值。

Answer 3

您似乎试图将其映射到另一个对象。

首先，尝试阅读和理解数组方法，您可以检查：

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array

对于地图方法，您可以检查：

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map

作为具体答案，您可以执行以下操作：

const mappedData = data.map(function(item) {
    return {
        scheme_name: item.scheme_name,
        NAV: item.NAV
    };
});

这将为您返回简化版本的数组。

之后，您可以将其转换为类似以下的字符串：

let solution = `You have ${mappedData.length} schemes linked to your account. `;
mappedData.forEach(function(mapped) {
    solution += mapped.scheme_name + ' is ' + mapped.NAV + ' '
});

注意：我展示了map方法，用于深入了解您可以做什么，通常不需要简化，可以直接用于每个版本。

Answer 4

我为您创建了示例fiddle。您需要遍历主对象中的每个对象，并将所有信息存储在外部。

data.forEach(function(item) {
  console.log(item.scheme_name);
});

结合javascript对象的属性值和显示

4 个答案: