Question

我想创建一个具有三个不同增量的序列。例如从6到15增加0.7。跟随顺序应从上一个顺序的最后一个编号开始（在本例中为14.4）。通过这种方式，我想根据直径类别（小6-14.99；中15-29.99；大> 30）对树的直径增量进行建模。

    dbh <- c(seq(from = 6, to = 15, by = temp$DBH_growth[temp$dbh_class == "sma"]),
     seq(from = 15, to = 30, by = temp$DBH_growth[temp$dbh_class == "med"]),
     seq(from = 30, to = 300, by = temp$DBH_growth[temp$dbh_class == "big"]))

类似于此代码，但从序列的最后一个数字开始。

Answer 1

类似这样的东西

sma <- seq(6, 15, .7)
med <- seq(max(sma), 30, 1)
lar <- seq(max(med), 300, 1.4)
dbh <- c(sma, med, lar)

假设.7,1,1.4分别是小号，中号，大号或您的情况下的增量

sma <- seq(6, 15, temp$DBH_growth[temp$dbh_class == "sma"])
med <- seq(max(sma), 30, temp$DBH_growth[temp$dbh_class == "med"])
lar <- seq(max(med), 300, temp$DBH_growth[temp$dbh_class == "big"])

dbh <- c(sma, med, lar)

seq（）具有多个增量

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