如何在视图中的URL中获取参数并基于此过滤查询？ 我也想在网址中有多个参数，它们都是可选的？ 为了清楚地传达需求，请看一下urls.py中的网址：
url(r'^search/(?P<insurance>\D+)/(?P<area>\D+)/(?P<slug>\D+)/(?P<illness>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>\D+)/(?P<area>\D+)/(?P<slug>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>\D+)/(?P<slug>\D+)/(?P<illness>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>\D+)/(?P<area>\D+)/(?P<illness>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>\D+)/(?P<area>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>\D+)/(?P<slug>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>\D+)/(?P<area>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>\D+)/(?P<illness>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<insurance>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>\D+)/(?P<slug>\D+)/(?P<illness>\D+)$',new_search,name='new_search'),
url(r'^search/(?P<area>\D+)/(?P<slug>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>\D+)/(?P<illness>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<area>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>\D+)/(?P<illness>\D+)/$',new_search,name='new_search'),
url(r'^search/(?P<slug>\D+)/$',new_search,name='new_search'),
如何基于views.py中的那些网址过滤查询集