Question

cre是当前累计的学分，因为当前学时为12，所以乘以12。

req是我达到目标CGPA的最低学分的等式。

cre = data[0][0]*12;
req = (26*data[0][1])-cre;

在下学期，将选修4门科目，每门科目的学时为4,4,3,3.total up =14。所以我得出了这一点，我想做的是创建一个循环并将x递增0.01，直到子的总学分达到要求：

if(((56+cre)/26)>data[0][1]) {
        do {

             double x = i/100;

             sub1 = 4*x;
             sub2 = 4*x;
             sub3 = 3*x;
             sub4 = 3*x;

            total = sub1 + sub2 + sub3 + sub4;

                i++;



        } while (total<req);

        System.out.println(sub1/4.0);
        System.out.println(sub2/4.0);
        System.out.println(sub3/3.0);
        System.out.println(sub4/3.0);
        }

最后，我尝试将所有子项分别除以4和3，以找到每个受试者达到目标CGPA所需的最低gpa。

Answer 1

没有更多信息，我们只能猜测。很有可能是这个问题：

double x = i/100;

如果i是整数，则每i小于100等于零。您可能需要浮点除法。

double x = i/100.0;

您可以通过一些数学找到一个更简单的解决方案。首先，计算GPA的公式为

sum(grade_points_for_all_classes) / total_hours = GPA

任何课程的“成绩点”都是

grade * credit_hours

现在，我们要计算所有新班级的最低成绩（min_grade），以达到新的desired_gpa。等式应该是

(sum(grade_points_for_prev_classes) + (min_grade * sum(new_class_hours)) / total_hours = desired_gpa

total_hours是总学时数（新旧班级）。解决min_grade，我们得到：

min_grade = (desired_gpa * total_hours - sum(grade_points_for_prev_classes)) / sum(new_class_hours)

示例：

public static void main (String[] args) throws java.lang.Exception
{
    double goalGPA = 3.25;

    // Create an array of previous courses
    double [][] prevCourses = {
        {4, 4.0},
        {4, 3.0},
        {3, 2.0},
        {2, 1.0}
    };

    // Calc grade points for prev courses
    // and also total credit hours for prev courses
    double gradePointsPrevCourses = 0;
    int totalCreditHours = 0;
    for (double [] c : prevCourses) {
        gradePointsPrevCourses += c[0] * c[1];
        totalCreditHours += c[0];
    }

    // Create an array of the new courses
    // Not concerned with grades yet so fill with zero
    double [][] newCourses = {
        {4, 0.0},
        {4, 0.0},
        {3, 0.0},
        {3, 0.0}
    };

    // Calc new credit hours
    // and add to prev credit hours
    int newCreditHours = 0;
    for (double [] c : newCourses) {
        newCreditHours += c[0];
    }
    totalCreditHours += newCreditHours;

    // Solve
    double minGrade = (goalGPA * totalCreditHours - gradePointsPrevCourses) / newCreditHours;
    if (minGrade <= 4.0) {
        System.out.println(String.format("You will need a %.2f in all classes to get a %.2f GPA", minGrade, goalGPA));
    }
    else {
        System.out.println(String.format("Sorry, a %.2f is unobtainable.", goalGPA));
    }
}

询问学生当前的CGPA和目标CGPA，然后计算达到目标CGPA的最低成绩

1 个答案: