Question

我有一个将字符串分成两行的函数。它将根据空格的位置中断字符串：

 splitSentenceInHalfCC(sentence: string): [string, string] {
    let middle = Math.floor(sentence.length / 2);
    let before = sentence.lastIndexOf(' ', middle);
    let after = sentence.indexOf(' ', middle + 1);


    if (middle - before < after - middle || after === -1) {
      middle = before;
    } else {
      middle = after;
    }

    let s1 = sentence.substr(0, middle);
    let s2 = sentence.substr(middle + 1);

    return [s1, s2];
  }

我现在想做的是添加一个if语句，如果空格为零，它将在前15个字符之后将字符串分成两行。我该如何实现？我对此很陌生，所以不确定如何进行。谢谢。

Example #1 input: This is a Store name and it is detailed.
Example #1 output: This is a Store name 
                   and it is detailed.
Example #2 input: Thisisjustalongstorenamewithnospaces.
Example #2 output: Thisisjustalongstorename
                   withnospaces.

Answer 1

我认为您需要做的就是在函数的开头检查语句race <- sample(c("A", "B", "C", "D"), size = 100, replace = T) recidivated <- sample(c(TRUE, FALSE), size = 100, replace = T) df <- data.frame(race, recidivated) df %>% group_by(race) %>% summarize(recidRate = mean(recidivated)) %>% ggplot(aes(race, recidRate)) + geom_bar(stat = "identity")是否为空格-如果不是，则返回包含两个项目的数组，语句{{1 }}从0到35，然后从35开始。（当然，如果要更改字符数，只需更改提供给.includes的{{1}}参数）

slice

Answer 2

检查字符串是否包含空格。

 splitSentenceInHalfCC(sentence: string): [string, string] {
    let middle = Math.floor(sentence.length / 2);
    let before = sentence.lastIndexOf(' ', middle);
    let after = sentence.indexOf(' ', middle + 1);


    if (middle - before < after - middle || after === -1) {
      middle = before;
    } else {
      middle = after;
    }

    if( before === -1 && after === -1 ){
       middle = 35;
    }

    let s1 = sentence.substr(0, middle);
    let s2 = sentence.substr(middle + 1);

    return [s1, s2];
  }

注意：您可能希望数字35基于字符串的长度。

根据空格和长度将字符串分为两行的条件语句

2 个答案: