Question

我是正则表达式匹配的新手，我的字符串如下所示

"karthika has symptoms cold,cough her gender is female and his age is 45"

在第一个匹配的字符串中，我将检查关键字“症状”，然后选择关键字的下一个单词，如下所示：

regexp = re.compile("symptoms\s(\w+)")
symptoms = regexp.search(textoutput).group(1)

这将使症状值为“冷”，但是我在文本中存在多个症状，因此在第二步中，我需要在“冷”之后检入是否存在逗号（，），如果存在逗号表示我需要在正则表达式“咳嗽”后立即打印值。

请帮助我实现这一目标。

Answer 1

您可以使用正则表达式来查找'symptoms'之后的第一个单词，并可以选择以科马，马比空格和更多单词字符开头的更多匹配项：

import re

pattern = r"symptoms\s+(\w+)(?:,\s*(\w+))*"
regex = re.compile(pattern)

t = "kathy has symptoms cold,cough her gender is female. john's symptoms  hunger, thirst."
symptoms = regex.findall(t)

print(symptoms)

输出：

[('cold', 'cough'), ('hunger', 'thirst')]

说明：

r"symptoms\s+(\w+)(?:,\s*(\w+))*"
# symptoms\s+                      literal symptoms followed by 1+ whitepsaces 
#            (\w+)                 followed by 1+ word-chars (first symptom) as group 1
#                 (?:,        )*   non grouping optional matches of comma+spaces
#                        (\w+)     1+ word-chars (2nd,..,n-th symptom) as group 2-n

备用方式：

import re

pattern = r"symptoms\s+(\w+(?:,\s*\w+)*(?:\s+and\s+\w+)?)"

regex = re.compile(pattern)

t1 = "kathy has symptoms cold,cough,fever and noseitch her gender is female. "
t2 = "john's symptoms  hunger, thirst."
symptoms = regex.findall(t1+t2)

print(symptoms)

输出：

['cold,cough,fever and noseitch', 'hunger, thirst']

这仅适用于“英国”英语-的

"kathy has symptoms cold,cough,fever, and noseitch"

只会导致cold,cough,fever, and作为匹配项。

您可以在','和" and "拆分每个匹配项，以获取单个原因：

sym = [ inner.split(",") for inner in (x.replace(" and ",",") for x in symptoms)] 
print(sym)

输出：

[['cold', 'cough', 'fever', 'noseitch'], ['hunger', ' thirst']]

Answer 2

您可以使用正则表达式捕获组例如，

# the following pattern looks for 
# symptoms<many spaces><many word chars><comma><many word chars>

s_re = re.compile(r"symptoms\s+\w+,(\w+)")

完整代码是

import re
from typing import Optional

s_re = re.compile(r"symptoms\s+\w+,(\w+)")

def get_symptom(text: str) -> Optional[str]:
    found = s_re.search(text)

    if found:
      return found.group(1)
    return None

搜索字符串中的comma（，）（如果存在逗号），然后在python中的逗号后打印立即字

2 个答案: