Question

我有以下字符串。我只需要删除单引号之间的空格。其余部分在该行中应该完好无损

+amk=0 nog = 0 nf=1 par=1 mg =0.34e-6 sd='((nf != 1) ? (nf-1)) :0)' sca=0 scb=0 scc=0  pj='2* ((w+7.61e-6) + (l+8.32e-6 ))'

所以输出应该是

+amk=0 nog = 0 nf=1 par=1 mg =0.34e-6 sd='((nf!=1)?(nf-1)):0)' sca=0 scb=0 scc=0  pj='2*((w+7.61e-6)+(l+8.32e-6))'

是否可以使用单个Regex语句执行此操作？或需要多行？

Answer 1

作为替代方案，您可能要考虑有限状态机。我总是忘记了该库，但是自行创建它非常简单。像这样：

def remove_quoted_whitespace(input_str):
    """
    Remove space if it is quoted.

    Examples
    --------
    >>> remove_quoted_whitespace("mg =0.34e-6 sd='((nf != 1) ? (nf-1)) :0)'")
    "mg =0.34e-6 sd='((nf!=1)?(nf-1)):0)'"
    """
    output = []
    is_quoted = False
    quotechars = ["'"]
    ignore_chars = [' ']
    for c in input_str:
        if (c in ignore_chars and not is_quoted) or c not in ignore_chars:
            output.append(c)
        if c in quotechars:
            is_quoted = not is_quoted
    return ''.join(output)

另请参阅：Is list join really faster than string concatenation in python?

如何仅在引号之间的部分中删除空格

1 个答案: