Question

我想编写一个通过标记分解字符串的函数，到目前为止，我想到了以下内容：

#include <cstring>
#include <iostream>
#include <vector>
#define MAXLEN 20

void mytoken(std::string input, std::vector<std::string> & out);

int main() 
{
    std::vector<std::string> out;
    std::string txt = "XXXXXX-CA";
    mytoken(txt, out);
    std::cout << "0: " << out[0] <<std::endl;
    std::cout << "1: " << out[1] <<std::endl;
}

void mytoken(std::string instr, std::vector<std::string> & out) {
    std::vector<std::string> vec;
    char input[MAXLEN] = {0};
    strcpy(input, instr.c_str());
    char *token = std::strtok(input, "-");
    while (token != NULL) {
        std::cout << token << '\n';
        token = std::strtok(NULL, "-");
        out.push_back(token);
    }    
}

产生以下输出：

terminate called after throwing an instance of 'std::logic_error'
  what():  basic_string::_M_construct null not valid
XXXXXX
CA
bash: line 7: 21987 Aborted                 (core dumped) ./a.out

我不知道为什么。

Answer 1

最好使用“ c ++样式”函数：它更简单，更易读：

#include <sstream>

void mytoken(std::string instr, std::vector<std::string> & out)
{
    std::istringstream ss(instr);
    std::string token;
    while(std::getline(ss, token, '-'))
    {
        std::cout << token << '\n';
        out.push_back(token);
    }
}

为使示例正常工作，您需要更改循环中的操作顺序：

//...
while(token != NULL)
{
    out.push_back(token);
    std::cout << token << '\n';
    token = std::strtok(NULL, "-");
}

C ++中的字符串标记化引发段错误

1 个答案: