Question

我正在测试在计算着色器中写入2D和3D纹理，输出由32位浮点数组成的梯度噪声纹理。写入2D纹理效果很好，但是写入3D纹理则不行。与2D纹理相比，创建3D纹理时还需要考虑其他因素吗？

下面如何定义3D纹理的代码：

HRESULT BaseComputeShader::CreateTexture3D(UINT width, UINT height, UINT depth, DXGI_FORMAT format, ID3D11Texture3D** texture)
{

D3D11_TEXTURE3D_DESC textureDesc;
ZeroMemory(&textureDesc, sizeof(textureDesc));
textureDesc.Width = width;
textureDesc.Height = height;
textureDesc.Depth = depth;
textureDesc.MipLevels = 1;
textureDesc.Format = format;
textureDesc.Usage = D3D11_USAGE_DEFAULT;
textureDesc.BindFlags = D3D11_BIND_SHADER_RESOURCE | D3D11_BIND_UNORDERED_ACCESS;
textureDesc.CPUAccessFlags = 0;
textureDesc.MiscFlags = 0;

return renderer->CreateTexture3D(&textureDesc, 0, texture);

}

HRESULT BaseComputeShader::CreateTexture3DUAV(UINT depth, DXGI_FORMAT format, ID3D11Texture3D** texture, ID3D11UnorderedAccessView** unorderedAccessView)
{

D3D11_UNORDERED_ACCESS_VIEW_DESC uavDesc;
ZeroMemory(&uavDesc, sizeof(uavDesc));
uavDesc.Format = format;
uavDesc.ViewDimension = D3D11_UAV_DIMENSION_TEXTURE3D;
uavDesc.Texture3D.MipSlice = 0;
uavDesc.Texture3D.FirstWSlice = 0;
uavDesc.Texture3D.WSize = depth;

return renderer->CreateUnorderedAccessView(*texture, &uavDesc, unorderedAccessView);

}

HRESULT BaseComputeShader::CreateTexture3DSRV(DXGI_FORMAT format, ID3D11Texture3D** texture, ID3D11ShaderResourceView** shaderResourceView)
{

D3D11_SHADER_RESOURCE_VIEW_DESC srvDesc;
ZeroMemory(&srvDesc, sizeof(srvDesc));
srvDesc.Format = format;
srvDesc.ViewDimension = D3D11_SRV_DIMENSION_TEXTURE3D;
srvDesc.Texture3D.MostDetailedMip = 0;
srvDesc.Texture3D.MipLevels = 1;

return renderer->CreateShaderResourceView(*texture, &srvDesc, shaderResourceView);

}

以及如何在计算着色器中写入它：

// The texture we're writing to
RWTexture3D<float> outputTexture : register(u0);

[numthreads(8, 8, 8)]
void main(uint3 DTid : SV_DispatchThreadID)
{

float noiseValue = 0.0f;
float value = 0.0f;
float localAmplitude = amplitude;
float localFrequency = frequency;

// Loop for the number of octaves, running the noise function as many times as desired (8 is usually sufficient)
for (int k = 0; k < octaves; k++)
{

    noiseValue = noise(float3(DTid.x * localFrequency, DTid.y * localFrequency, DTid.z * localFrequency)) * localAmplitude;

    value += noiseValue;

    // Calculate a new amplitude based on the input persistence/gain value
    // amplitudeLoop will get smaller as the number of layers (i.e. k) increases
    localAmplitude *= persistence;
    // Calculate a new frequency based on a lacunarity value of 2.0
    // This gives us 2^k as the frequency
    // i.e. Frequency at k = 4 will be f * 2^4 as we have looped 4 times
    localFrequency *= 2.0f;

}

// Output value to 2D index in the texture provided by thread indexing
outputTexture[DTid.xyz] = value;

}

最后，我如何运行着色器：

// Set the shader
deviceContext->CSSetShader(computeShader, nullptr, 0);
// Set the shader's buffers and views
deviceContext->CSSetConstantBuffers(0, 1, &cBuffer);
deviceContext->CSSetUnorderedAccessViews(0, 1, &textureUAV, nullptr);

// Launch the shader
deviceContext->Dispatch(512, 512, 512);

// Reset the shader now we're done
deviceContext->CSSetShader(nullptr, nullptr, 0);

// Reset the shader views
ID3D11UnorderedAccessView* ppUAViewnullptr[1] = { nullptr };
deviceContext->CSSetUnorderedAccessViews(0, 1, ppUAViewnullptr, nullptr);

// Create the shader resource view for access in other shaders
HRESULT result = CreateTexture3DSRV(DXGI_FORMAT_R32_FLOAT, &texture, &textureSRV);
if (result != S_OK)
{

    MessageBox(NULL, L"Failed to create texture SRV after compute shader execution", L"Failed", MB_OK);
    exit(0);

}

Answer 1

我的简单错误。计算着色器线程的数量受到限制。在计算着色器中，您最多只能有1024个线程，并且调度调用最多只能调度65535个线程组。 HLSL编译器将解决前一个问题，而Visual C ++编译器将不解决后一个问题。

Answer 2

如果您创建512 * 512 * 512的纹理（这似乎是您要实现的目标），则需要按组划分调度：

deviceContext->Dispatch(512 / 8, 512 / 8, 512 / 8);

在您先前的情况下，调度是： 512 * 8 * 512 * 8 * 512 * 8 = 68719476736单位

很可能触发了超时检测并导致驱动程序崩溃

65535的限制是每个尺寸，因此在您的情况下，您可以完全安全地运行它。

最后一个，您可以在创建3d纹理之后（在分派调用之前）立即创建着色器资源视图和无序视图。

通常建议这样做，以避免混淆上下文代码和资源创建代码。

在创建资源时，您的检查也无效：

if (result != S_OK)

HRESULT成功条件为> = 0

您可以改用内置宏，例如：

if (SUCCEEDED(result))

DirectX-写入导致显示驱动器故障的3D纹理

2 个答案: