为什么在python中的按钮上不显示按钮文本?

时间:2018-11-18 16:30:52

标签: python tkinter

我用tkinter python制作了一个注册程序。该程序工作正常,但是按钮没有文本。这是代码:

from tkinter import *
import sqlite3

root = Tk()
root.geometry('500x500')
root.title("Registration Form")

Fullname = StringVar()
Email = StringVar()
var = IntVar()
c = StringVar()
var1 = IntVar()


def database():
    name1 = Fullname.get()
    email = Email.get()
    gender = var.get()
    country = c.get()
    prog = var1.get()
    conn = sqlite3.connect('tennis.db')
    with conn:
        cursor = conn.cursor()
    cursor.execute(
        'CREATE TABLE IF NOT EXISTS Student (Fullname TEXT,Email TEXT,Gender TEXT,country TEXT,Programming TEXT)')
    cursor.execute('INSERT INTO Student (FullName,Email,Gender,country,Programming) VALUES(?,?,?,?,?)',
               (name1, email, gender, country, prog,))
    conn.commit()


label_0 = Label(root, text="Registration form", width=20, font=("bold", 20))
label_0.place(x=90, y=53)

label_1 = Label(root, text="FullName", width=20, font=("bold", 10))
label_1.place(x=80, y=130)

entry_1 = Entry(root, textvar=Fullname)
entry_1.place(x=240, y=130)

label_2 = Label(root, text="Email", width=20, font=("bold", 10))
label_2.place(x=68, y=180)

entry_2 = Entry(root, textvar=Email)
entry_2.place(x=240, y=180)

label_3 = Label(root, text="Gender", width=20, font=("bold", 10))
label_3.place(x=70, y=230)

Radiobutton(root, text="Male", padx=5, variable=var, value=1).place(x=220, y=230)
Radiobutton(root, text="Female", padx=20, variable=var, value=2).place(x=290, y=230)

label_4 = Label(root, text="City", width=20, font=("bold", 10))
label_4.place(x=70, y=280)

list1 = ['Africa', 'Nigeria', 'Oshawa', 'Other'];

droplist = OptionMenu(root, c, *list1)
droplist.config(width=15)
c.set('select your city')
droplist.place(x=240, y=280)

label_4 = Label(root, text="Skill Level", width=20, font=("bold", 10))
label_4.place(x=85, y=330)
var2 = IntVar()
var3 = IntVar()

Checkbutton(root, text="Beginner", variable=var1).place(x=200, y=330)

Checkbutton(root, text="Intermiadiate", variable=var2).place(x=280, y=330)

Checkbutton(root, text="Advanced", variable=var3).place(x=390, y=330)

def printdatshuff():
    conn = sqlite3.connect('tennis.db')
    with conn:
        cursor = conn.cursor()
    cursor.execute("SELECT * FROM Student")
    result = cursor.fetchall()
    conn.commit()
    for r in result:
        print(r)

johy = Button(root, text='Submit', width=20, bg='brown', fg='white', command=database)
johy.place(x=180, y=380)
johy1 = Button(root, text='See all', width=20, bg='brown', fg='white', command=printdatstuff)
johy1.place(x=180, y=400)

root.mainloop()

程序的结尾是按钮代码所在的位置。我指定按钮显示文本,但不显示文本。如果有人知道如何解决此问题,将不胜感激。 谢谢, 贾马尔(Jamal)

1 个答案:

答案 0 :(得分:0)

您正在将前景设置为白色,这也是OSX上的默认背景色。 OSX不允许您更改背景颜色。因此,您在白色背景上有白色文字。

如果将fg属性更改为“白色”以外的内容,则会看到文本。