Question

我有以下json

[
 {"firstname": "john", "lastname": "doe"},
 {"firstname": "john", "lastname": "smith"},
 {"firstname": "jane", "lastname": "smith"},
 {"firstname": "jane", "lastname": "doe"},
 {"firstname": "joe", "lastname": "smith"},
 {"firstname": "joe", "lastname": "doe"},
 {"firstname": "steve", "lastname": "smith"},
 {"firstname": "jack", "lastname": "doe"}
]

我想计算重复的名字

重复计数3

不重复的名字计数

非重复计数2

我试图计算存储桶的数量，但是似乎要计算所有存储桶是重复的还是不重复的

GET mynames/_search
{
"aggs" : {
    "name_count" : {
        "terms" : {
            "field" : "firstname.keyword",
            "min_doc_count": 2
        }
    },
"count":{
  "cardinality": {
    "field": "firstname.keyword"
  }
}
}

Answer 1

我在这里利用了几种聚合。以下是我使用过的列表。列表的顺序是聚合的执行顺序。

重复

非重复

Terms Aggregation
- Bucket Selector（作为子聚合）
Sum Bucket Selector

汇总查询：

POST <your_index_name>/_search
{  
   "size":0,
   "aggs":{  
      "duplicate_aggs":{  
         "terms":{  
            "field":"firstname.keyword",
            "min_doc_count":2
         }
      },
      "duplicate_bucketcount":{  
         "stats_bucket":{  
            "buckets_path":"duplicate_aggs._count"
         }
      },
      "nonduplicate_aggs":{  
         "terms":{  
            "field":"firstname.keyword"
         },
         "aggs":{  
            "equal_one":{  
               "bucket_selector":{  
                  "buckets_path":{  
                     "count":"_count"
                  },
                  "script":"params.count == 1"
               }
            }
         }
      },
      "nonduplicate_bucketcount":{  
         "sum_bucket":{  
            "buckets_path":"nonduplicate_aggs._count"
         }
      }
   }
}

响应

{
  "took": 10,
  "timed_out": false,
  "_shards": {
    "total": 5,
    "successful": 5,
    "skipped": 0,
    "failed": 0
  },
  "hits": {
    "total": 8,
    "max_score": 0,
    "hits": []
  },
  "aggregations": {
    "duplicate_aggs": {
      "doc_count_error_upper_bound": 0,
      "sum_other_doc_count": 0,
      "buckets": [
        {
          "key": "jane",
          "doc_count": 2
        },
        {
          "key": "joe",
          "doc_count": 2
        },
        {
          "key": "john",
          "doc_count": 2
        }
      ]
    },
    "nonduplicate_aggs": {
      "doc_count_error_upper_bound": 0,
      "sum_other_doc_count": 0,
      "buckets": [
        {
          "key": "jack",
          "doc_count": 1
        },
        {
          "key": "steve",
          "doc_count": 1
        }
      ]
    },
    "duplicate_bucketcount": {
      "count": 3,
      "min": 2,
      "max": 2,
      "avg": 2,
      "sum": 6
    },
    "nonduplicate_bucketcount": {
      "value": 2
    }
  }
}

请注意，在上述响应中，我们有一个duplicate_bucketcount.count密钥，其值3将会显示存储桶计数，该存储桶计数是重复的密钥数目。

让我知道是否有帮助！

Elasticsearch-计算重复值和唯一值

1 个答案:

汇总查询：

响应