Question

我尝试解析此JSON地址，但失败了。我尝试的代码失败，没有数据反映。你能帮我吗？

我的代码；

private void parseJSON() {
    final String url = "json website";
    JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null,
            new Response.Listener<JSONObject>() {
                @Override
                public void onResponse(JSONObject response) {
                    try {
                        JSONArray jsonArray = response.getJSONArray(null);
                        for (int i = 0; i < jsonArray.length(); i++) {
                            JSONObject hit = jsonArray.getJSONObject(i);
                            String imageref = hit.getString(null);

                            mExampleList.add(new ExampleItemRef(imageref));
                        }

此JSON;

[
"https://www.asdasd.com/images/r/a.png",
"https://www.asdasd.com/images/r/b.png",
"https://www.asdasd.com/images/r/c.png",
"https://www.asdasd.com/images/r/d.png",
"https://www.asdasd.com/images/r/e.png"
]

Answer 1

只需从代码中删除所有不必要的部分，然后按如下所示进行更改即可。创建数组时需要放置json字符串

private void parseJSON() {
    final String url = "json website";
    JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null,
            new Response.Listener<JSONObject>() {
                @Override
                public void onResponse(JSONObject response) {
                    try {
                        JSONArray jsonArray = response.getJSONArray(jsonString);
                          for (int i = 0; i < jsonArray.length(); i++) {
                                    mExampleList.add(new ExampleItemRef(jsonArray.getString(i)));
                                }
                        }

Answer 2

您可以这样：

ArrayList < ExampleItemRef > mExampleList = new ArrayList <ExampleItemRef > ();
String jsonStr =
    "[ \"https://www.asdasd.com/images/r/a.png\", \"https://www.asdasd.com/images/r/b.png\", \"https://www.asdasd.com/images/r/c.png\", \"https://www.asdasd.com/images/r/d.png\", \"https://www.asdasd.com/images/r/e.png\" ]";

try {
    JSONArray jsonArray = new JSONArray(jsonStr);
    for (int i = 0; i < jsonArray.length(); i++) {
        String imageref = jsonArray.getString(i);
        mExampleList.add(new ExampleItemRef(imageref));
    }
} catch (JSONException e) {
    e.printStackTrace();
}

代码是自我解释的，因此没有注释，希望对您有所帮助

已编辑：尝试此操作

private void parseJSON() {
    final String url = "json website";
    JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null,
            new Response.Listener<JSONObject>() {
                @Override
                public void onResponse(JSONObject response) {
                    try {
                        JSONArray jsonArray = new JSONArray(response.toString());
                        for (int i = 0; i < jsonArray.length(); i++) {
                           String imageref = jsonArray.getString(i);
                           mExampleList.add(new ExampleItemRef(imageref));
                        }

如何解析空名称json数组（仅字符串）

2 个答案: