我有一个大小为x的numpy数组,我需要用700 true填充。
例如:
a = np.zeros(5956)
如果我想用70%的True填充,我可以这样写:
msk = np.random.rand(len(a)) < 0.7
b = spam_df[msk]
但是,如果我确实需要700个真实值,而其余的则为假,该怎么办?
答案 0 :(得分:3)
import numpy as np
x = 5956
a = np.zeros((x), dtype=bool)
random_places = np.random.choice(x, 700, replace=False)
a[random_places] = True
答案 1 :(得分:2)
@implementation nextViewController
{
NSArray *tableData;
NSArray * arrayfortable;
NSMutableArray * selectedIndexpath;
}
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
UITableViewCell* cell = [tableView cellForRowAtIndexPath:indexPath];
NSMutableArray *selectedIndexpath = [[NSMutableArray alloc]init];
selectedIndexpath = [selectedIndexpath arrayByAddingObject:[tableData objectAtIndex:indexPath.row]];
NSLog(@"selected",selectedIndexpath);
if (cell.accessoryType == UITableViewCellAccessoryNone) {
cell.accessoryType = UITableViewCellAccessoryCheckmark;
__selectedPath = indexPath;
} else {
cell.accessoryType = UITableViewCellAccessoryNone;
__selectedPath = nil;
}
}
示例-数组中应该有5个元素,其中3个为True,其余为False。
import numpy as np
zeros = np.zeros(5956-700, dtype=bool)
ones=np.ones(700, dtype=bool)
arr=np.concatenate((ones,zeros), axis=0, out=None)
np.random.shuffle(arr)#Now, this array 'arr' is shuffled, with 700 Trues and rest False