考虑一下我们是否有一个包含一个字段的表单,供用户这样上传文件:
class PoscastForm(forms.ModelForm):
class Meta:
fields = ("title", "message", "channel", "file", "tag")
model = models.Podcast
def __ini__(self, *args, **kwargs):
user = kwargs.pop("user", None)
super().__init__(*args, **kwargs)
if user is not None:
self.fields["channel"].queryset = (
models.Channel.objects.filter(
pk__in = user.channels.value_list('channel__pk')
)
)
以及播客模型:
class Podcast(models.Model):
title = models.CharField(max_length=255, default='')
user = models.ForeignKey(User, related_name="podcasts",
on_delete=models.CASCADE, unique=False)
created_at = models.DateTimeField(auto_now=True)
channel = models.ForeignKey(Channel, related_name="podcasts",
null=True, blank=True,
on_delete=models.CASCADE)
message = models.TextField(blank=True, null=True)
message_html = models.TextField(editable=False)
tag = models.ForeignKey('podcasts.Tag', related_name="podcasts",
null=True, blank=True, on_delete=models.CASCADE)
file = models.FileField(blank=True, null=True, default='')
因此,当用户上传他的附件时,它将保存在我项目的根目录中!如何更改方向路径? 此表单的视图如下所示:
class CreatePodcast(LoginRequiredMixin, SelectRelatedMixin,
generic.CreateView):
fields = ("title", "message", "channel", "file", "tag")
model = models.Podcast
def form_valid(self, form):
self.object = form.save(commit=False)
self.object.user = self.request.user
self.object.save()
return super().form_valid(form)
答案 0 :(得分:2)
根据documentation,您可以在模型定义中定义文件路径
file = models.FileField(blank=True, null=True, default='', upload_to="your/path/")
如果您定义了MEDIA_ROOT,则上传的文件将被发送到MEDIA_ROOT
的子目录upload_to
。有关更多详细信息,请参见storage文档。
您还可以定义用户明智的上传目录。来自文档:
def user_directory_path(instance, filename):
# file will be uploaded to MEDIA_ROOT/user_<id>/<filename>
return 'user_{0}/{1}'.format(instance.user.id, filename)
# model defination
file = models.FileField(upload_to=user_directory_path)