Question

抱歉，我所知道的标题没有我想要的解释。

我正在为分发包创建一个配置文件，并且希望以多种方式定义en元素。

这些是我想要定义条目的不同方式：

properties:
  property1: ~
  property2: ~
  property3: Custom label3
  property4:
    label: Custom label4
    type: int

或

properties:
  - property1
  - property2
  - { property: property3, label: Custom label3 }
  - { property: property4, label: Custom label4, type: int }

两种配置都应具有以下结构：

"properties" => [
  "property1" => [
     "label": null
     "type": null
  ], 
  "property2" => [
     "label": null
     "type": null
  ], 
  "property3" => [
     "label": "Custom label 3"
     "type": null
  ], 
  "property4" => [
     "label": "Custom label 4"
     "type": "int"
  ], 
]

这是我当前拥有的代码：

->arrayNode('properties')
    ->useAttributeAsKey('property')
    ->arrayPrototype()
        ->beforeNormalization()
            ->ifString()->then(function($item) { return ['property' => $item]; })
        ->end()
        ->children()
            ->scalarNode('property')->defaultNull()->end()
            ->scalarNode('label')->defaultNull()->end()
            ->scalarNode('type')->defaultNull()->end()
        ->end()
    ->end()
->end()

请问我收到的第一个代码如下结果，这几乎是完美的：

"properties" => array:4 [
  "property1" => array:3 [
    "property" => null
    "label" => null
    "type" => null
  ]
  "property2" => array:3 [
    "property" => null
    "label" => null
    "type" => null
  ]
  "property3" => array:3 [
    "property" => "Custom label3"
    "label" => null
    "type" => null
  ]
  "property4" => array:3 [
    "label" => "Custom label4"
    "type" => "int"
    "property" => null
  ]
]

在每个条目中都有"property" => null。 如何删除密钥中已经存在的属性？

在第二个示例中，我收到以下结果：

"properties" => array:4 [
  0 => array:3 [
    "property" => "property1"
    "label" => null
    "type" => null
  ]
  1 => array:3 [
    "property" => "property2"
    "label" => null
    "type" => null
  ]
  "property3" => array:3 [
    "label" => "Custom label 3"
    "property" => null
    "type" => null
  ]
  "property4" => array:3 [
    "label" => "Custom label 4"
    "type" => "int"
    "property" => null
  ]
]

如您所见，前两个条目没有property作为键，它的编号类似于普通数组。 我该如何解决？

谢谢

Symfony配置树构建器useAttributeAsKey无法按预期工作

0 个答案: