拉伸或重采样一维数组

Question

这个问题可能很简单，我可能确实缺少一些基本知识，但是如何在C＃中内插一维数组？

让我们说我有n个元素组成的数组

package classwork7_2;
import java.util.*;
import java.io.*;

public class ClassWork7_2 {

public static void main(String[] args)throws IOException {

    Scanner s = new Scanner(System.in);

    int[] numbers = fileToArray();
    Arrays.sort(numbers);
    char quit = 'q';


    while (true) {
    System.out.print("Enter a number in the file: ");
    int numb = s.nextInt();
    int i = Arrays.binarySearch(numbers, numb);
    if (i < 0) {
        System.out.print("Number is not in file\n");
    } else {
        System.out.print("Number is in file\n");

    }
}


}

public static int[] fileToArray() throws IOException{

    Scanner s = new Scanner(System.in);
    int[] array = new int[7];

    System.out.print("Enter name of file: ");
    String filename = s.nextLine();

    File f = new File(filename);
    Scanner inputFile = new Scanner(f);
    int i = 0;

    while(inputFile.hasNext()){

       array[i] = inputFile.nextInt();
       i++;
    }
        inputFile.close();
        return array;
}
}

如何拉伸或压缩数组以使其具有n个值并对其进行插值，就像调整图像大小时那样，就是这样，而不是对数组进行斩波或添加零或空值。

例如，如果我要转换数组，使其具有n = 4个元素，请获取此

int[] array1 = new int[] { 1, 3, 5, 7, 1 };

我要尝试的操作与matlab的重采样功能相同 https://mathworks.com/help/signal/ref/resample.html

Answer 1

对于新数组比旧数组短的情况，我建议采用这种解决方案：

int[] array1 = new int[] { 1, 3, 5, 7, 9 };
int[] array2 = new int[4];

for (var i = 0; i < array2.Length; i++)
{
    var doubleIndex1 = (double)i * array1.Length / array2.Length;
    var index1 = (int)Math.Floor(doubleIndex1);
    var rel = doubleIndex1 - index1;

    array2[i] = (int)Math.Round((1.0 - rel) * array1[index1] + rel * array1[index1 + 1]);
}