Question

当我点击框架时，我在框架中添加了轻击手势，它将集中在拾取器上。问题是，当我轻按框架时，将显示选择器弹出窗口，而当我单击“取消”时，将再次显示选择器弹出窗口。我该如何解决？

 <Frame StyleClass="fieldFrame" x:Name="OutletFrame" CornerRadius="4" BorderColor="#e8eaed" HasShadow="False">
     <Frame.GestureRecognizers>
         <TapGestureRecognizer Tapped="TapGestureRecognizer_Tapped"/>
     </Frame.GestureRecognizers>
     <local:CustomPicker x:Name="codePicker" SelectedIndexChanged="codePicker_SelectedIndexChanged" Unfocused="codePicker_Unfocused" ItemsSource="{Binding RetailerCode}" ItemDisplayBinding="{Binding DisplayText}" StyleClass="fieldForm" IsEnabled="False">
         <local:CustomPicker.FontFamily>
             <OnPlatform x:TypeArguments="x:String">
                  <On Platform="Android" Value="HelveticaNeueLTPro-Lt.otf#HelveticaNeueLTPro-Lt"/>
             </OnPlatform>
          </local:CustomPicker.FontFamily>
      </local:CustomPicker>
 </Frame>

 private void TapGestureRecognizer_Tapped(object sender, EventArgs e)
 {
    if (!string.IsNullOrEmpty(entRetailer.Text))
    {
       codePicker.Focus();
       codePicker.IsEnabled = false;
    }
 }

Answer 1

跳过轻击手势，然后在ViewModel中添加一个bool属性，该属性控制是否启用Picker。

在您的XAML中，添加IsEnabled绑定：

<Picker x:Name="codePicker" 
        ItemsSource="{Binding RetailerCode}" 
        ItemDisplayBinding="{Binding DisplayText}"
        IsEnabled="{Binding CodePickerEnabled}" 
        ~~~
        />

在您的VM中，根据您的entRetailer.Text条件，添加一个true / false的bool属性：

public bool CodePickerEnabled { get { return (!String.IsNullOrEmpty(entRetailer.Text)); } }

框架点击手势Xamarin

1 个答案: