Question

除了当前季度到目前为止已经经过了多少个工作日之外，最好的方法是什么来拉动当前季度的工作日（星期一至星期五）？这是用于T-SQL / MS SQL

我目前有总天数，只需要删除周末...

datediff(dd, dateadd(qq, datediff(qq,0, getdate()),0), dateadd(qq, datediff(qq,0, getdate()) + 1 ,0)) as [Days in Quarter]

Answer 1

执行此操作的方法如下：

select
       dates.*

     , (DATEDIFF(dd, startofperiod, endofperiod) + 1)
      -(DATEDIFF(wk, startofperiod, endofperiod) * 2)
      -(CASE WHEN DATENAME(dw, startofperiod) = 'Sunday' THEN 1 ELSE 0 END) 
      -(CASE WHEN DATENAME(dw, endofperiod) = 'Saturday' THEN 1 ELSE 0 END)
      as wkdaysinperiod

     , (DATEDIFF(dd, startofperiod, today) + 1)
      -(DATEDIFF(wk, startofperiod, today) * 2)
      -(CASE WHEN DATENAME(dw, startofperiod) = 'Sunday' THEN 1 ELSE 0 END) 
      -(CASE WHEN DATENAME(dw, today) = 'Saturday' THEN 1 ELSE 0 END)
      as wkdaystodate
from (
    select 
          dateadd(qq, datediff(qq,0, getdate()),0)                     as startofperiod
        , dateadd(dd,-1,dateadd(qq, datediff(qq,0, getdate()) + 1 ,0)) as endofperiod
        , convert(date,getdate()) as today
    ) as Dates
;

上面看到的方法假定使用英语，因此，如果该方法不适合模数，则可以使用它来消除该依赖性，如下所示。

SQL Server中的“基准日期”是1900-01-01，它是一个星期一，因此，自该日期除以7、0之后的剩余天数是星期一，1，星期二，... 6周日。无论服务器datefirst的设置如何，都是如此。

select
       dates.*, ca.*

     , (DATEDIFF(dd, startofperiod, endofperiod) + 1)
      -(DATEDIFF(wk, startofperiod, endofperiod) * 2)
      -(CASE WHEN periodstartdaynum = 6 THEN 1 ELSE 0 END) /* Sunday */
      -(CASE WHEN periodenddaynum   = 5 THEN 1 ELSE 0 END) /* Saturday */
      as wkdaysinperiod

     , (DATEDIFF(dd, startofperiod, today) + 1)
      -(DATEDIFF(wk, startofperiod, today) * 2)
      -(CASE WHEN periodstartdaynum = 6 THEN 1 ELSE 0 END) /* Sunday */
      -(CASE WHEN todaydaynum       = 5 THEN 1 ELSE 0 END) /* Saturday */
      as wkdaystodate
from (
    select 
          dateadd(qq, datediff(qq,0, getdate()),0)                     as startofperiod
        , dateadd(dd,-1,dateadd(qq, datediff(qq,0, getdate()) + 1 ,0)) as endofperiod
        , convert(date,getdate()) as today
    ) as Dates
cross apply (
    select
          datediff(dd,0,startofperiod) % 7 as periodstartdaynum
        , datediff(dd,0,endofperiod) % 7   as periodenddaynum
        , datediff(dd,0,today) % 7         as todaydaynum
    ) ca
;

本季度的T-SQL工作日和本季度过去的工作日

1 个答案: