Question

我正在用OpenGL + C ++编写游戏。

生成动画的唯一方法是在glutDisplayFunc内定义一个无限循环。而我做到了。但是想象一下我有不同的gameObject，每个对象都有其draw()函数。

但是我想要一个函数来添加另一个对象。当我将它们保存在指针数组中时，此函数如下所示：

void display() {
    while (running) {
        glClearColor(0.0f, 0.0f, 0.0f, 1.0f); // Set background color to black and opaque
        glClear(GL_COLOR_BUFFER_BIT);         // Clear the color buffer
        if(objects_count != 0)
        for(unsigned int i = 0; i< objects_count - 1; i++) {
            (objects + i)->drawAsPoint();
        }
        glFlush();
        usleep(f60FPS);// Render now
    }
}

bool addRenderableObjectSync(GameEntity *object) {
    running = false;
    if(objects_count + 1>= objects_capacity) {
        //reallocating memory
        objects_capacity = round(objects_capacity * 1.5f);
        GameEntity * _new_objects = new GameEntity[objects_capacity];

        for(unsigned int i = 0; i < objects_count; i++) {
            _new_objects[i] = objects[i];
        }
        //now objects are safe to delete free
        delete[] objects;
        //now we move new array to objects and free the temporary one
        objects = _new_objects;
        delete[] _new_objects;
    }

    objects[objects_count] = *object;
    objects_count++;

    //delete *object as it no longer needed;
    delete object;
    return true; }

running是一个布尔值，它对显示函数内部的循环做出响应。

但是，绘制循环是无限的，我认为我需要一些可以破解running状态的异步函数，例如：

void Renderer::addRenderableObject(GameEntity *object) {
    //the reason we do it cause a game is in infinite loop which never ends
    //so we stop the game, add an object, and after fn finish we let it run again
    std::future<bool> fut = std:: async(addRenderableObjectSync, object);
    running = fut.get();
}

这是正确的解决方案吗？还是有更好的方法？

如何运行游戏循环并更改其对象？

0 个答案: