Question

我有一个位于多个子目录中的txt文件的csv列表（没有完整路径，看起来像：filea.txt）。我想将所有这些文件复制粘贴到一个目录中。

更麻烦的是，此CSV文件的CSV文件列表没有可重复的模式。此列表中的名称必须与目录中所有txt文件的列表匹配。

有人知道怎么做吗？

这是我的尝试：

 # Target and source
 source <- "C:/Users/blue/Desktop/A"
 target <- "C:/Users/blue/Desktop/B"

 # List of all txt files in main directory
 all.files  <- list.files(path = source,
                         recursive = TRUE,
                         pattern = ".txt",
                         full.names = TRUE)

 # List of specific txt files to extract
 extract.files <- read.csv(paste0(source, "/extract.csv"), head = FALSE, sep=",")

 # Somehow match list of specific files with list of all txt files here

 # Function to copy paste
 my.file.rename <- function(from, to) {
  todir <- dirname(to)
  if (!isTRUE(file.info(todir)$isdir)) dir.create(todir, recursive=TRUE)
  file.copy(from = from,  to = to)
 } 

 # Copy paste
 my.file.rename(from = source,to = target)

Answer 1

您不需要自定义功能。

# Target and source
source <- "C:/Users/blue/Desktop/A"
target <- "C:/Users/blue/Desktop/B"

# List of all txt files in main directory
all.files  <- list.files(path = source,
                         recursive = TRUE,
                         pattern = ".txt",
                         full.names = TRUE)

# List of specific txt files to extract
extract.files <- read.csv(paste0(source, "/extract.csv"), head = FALSE, sep=",")

toCopy <- all.files[which(basename(all.files) %in% unlist(extract.files))]

file.copy(toCopy, target)

从csv

1 个答案: