如何在if语句中执行grep?我想检查字符串是否包含子字符串。
DSU_DIFF="$(sudo php app/console d:s:u --dump-sql)"
# I want to check if the $DSU_DIFF contains the sub-string "Nothing to update"
if [ "$DSU_DIFF" | grep "Nothing to update" ]
then
echo "Contains substring"
else
echo "No substring contained"
fi
这在语法上是错误的,我应该如何尝试呢?
答案 0 :(得分:1)
为什么要为此使用case
?
您可以使用case "$DSU_DIFF" in
*'Nothing to update'*)
echo "Contains substring";;
*)
echo "No substring contained";;
esac
:
42ND-1000
W61ST-1000
TIFF-1000
THIR-1000
答案 1 :(得分:1)
@melpomene是正确的,但以防万一:
if echo "$DSU_DIFF" | grep "Nothing to update"; then
echo "Contains substring"
else
echo "No substring contained"
fi