如何检查是否从subscribe()中调用了服务方法

时间:2018-11-16 13:41:10

标签: angular typescript jasmine

我有一个响应式表单,在提交过程中,我向API发送了一个http请求,并基于其结果(成功/失败),我正在致电我的警报服务以显示警报:

public submit(formValues): void {
    this.generationProjectService
        .add(
            new CreateGenerationProjectRequest(
                formValues.selectedIndustry,
                formValues.selectedEdition,
                formValues.selectedDate,
                formValues.selectedTemplate,
                formValues.selectedImportant
            )
        )
        .subscribe(
            newGenerationProject => {
                this.domainEventService.onNewGenerationProject.emit(newGenerationProject);

                this.alertService.success('Project was successfully added to Overnight Generation');
            },
            () => {
                this.alertService.error('Something went wrong');
            }
        );
    this.close();
}

这很好用,我想测试一下,但是我很难理解。

fit('should notify failed project addition', () => {
    spyOn(generationProjectService, 'add').and.throwError('up');
    const errorSpy = spyOn(alertService, 'error').and.callThrough();

    component.submit({});

    fixture.detectChanges();

    fixture.whenStable().then(() => {
        expect(errorSpy).toHaveBeenCalledTimes(1);
    });
});

但这不起作用。

要使此功能正常工作,我必须在测试用例中进行哪些更改。还是我可以更改代码以使其更具可测试性?

1 个答案:

答案 0 :(得分:2)

我认为是因为您的间谍正在抛出Javascript错误而不是Observable发出错误,请尝试这种方式:

import { throwError } from 'rxjs';

spyOn(generationProjectService, 'add').and.returnValue(throwError('This is an error!'));