我正在尝试将sqlite中的一些图像缓存为nsdata,当我尝试使用sqlite3_exec和原始SQL字符串(作为NSString)插入字节数组时,我遇到了问题
NSData *imgData = UIImagePNGRepresentation(img);
NSString* sql = [NSString stringWithFormat:@"INSERT INTO persistedimg (imgx,idvalx) VALUES (%@,'%@')", imgData, idValue];
rc = sqlite3_exec(db, [sql UTF8String], callbackFunction, (void*)contextObject, &zErrMsg);
但上面的问题是我将NSData直接添加到sql字符串而不是字节。
我想做这样的事情
... [imgData bytes], [imgData length]
但是因为我没有使用典型的“_bind_blob”方法,所以我不知道怎么做原始字符串
更新
我正在使用一个我想坚持使用的包装器,只需编写一个新方法来支持图像插入/查询命令
以下是我到目前为止的整个包装类
**
#import "SQLiteAccess.h"
#import <sqlite3.h>
@implementation SQLiteAccess
+ (NSString *)pathToDB {
NSString *dbName = @"test123";
NSString *originalDBPath = [[NSBundle mainBundle] pathForResource:dbName ofType:@"db"];
NSString *path = nil;
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *appSupportDir = [paths objectAtIndex:0];
NSString *dbNameDir = [NSString stringWithFormat:@"%@/test123", appSupportDir];
NSFileManager *fileManager = [NSFileManager defaultManager];
BOOL isDir = NO;
BOOL dirExists = [fileManager fileExistsAtPath:dbNameDir isDirectory:&isDir];
NSString *dbPath = [NSString stringWithFormat:@"%@/%@.db", dbNameDir, dbName];
if(dirExists && isDir) {
BOOL dbExists = [fileManager fileExistsAtPath:dbPath];
if(!dbExists) {
NSError *error = nil;
BOOL success = [fileManager copyItemAtPath:originalDBPath toPath:dbPath error:&error];
if(!success) {
NSLog(@"error = %@", error);
} else {
path = dbPath;
}
} else {
path = dbPath;
}
} else if(!dirExists) {
NSError *error = nil;
BOOL success =[fileManager createDirectoryAtPath:dbNameDir attributes:nil];
if(!success) {
NSLog(@"failed to create dir");
}
success = [fileManager copyItemAtPath:originalDBPath toPath:dbPath error:&error];
if(!success) {
NSLog(@"error = %@", error);
} else {
path = dbPath;
}
}
return path;
}
+ (NSNumber *)executeSQL:(NSString *)sql withCallback:(void *)callbackFunction context:(id)contextObject {
NSString *path = [self pathToDB];
sqlite3 *db = NULL;
int rc = SQLITE_OK;
NSInteger lastRowId = 0;
rc = sqlite3_open([path UTF8String], &db);
if(SQLITE_OK != rc) {
NSLog(@"Can't open database: %s\n", sqlite3_errmsg(db));
sqlite3_close(db);
return nil;
} else {
char *zErrMsg = NULL;
NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init];
rc = sqlite3_exec(db, [sql UTF8String], callbackFunction, (void*)contextObject, &zErrMsg);
if(SQLITE_OK != rc) {
NSLog(@"Can't run query '%@' error message: %s\n", sql, sqlite3_errmsg(db));
sqlite3_free(zErrMsg);
}
lastRowId = sqlite3_last_insert_rowid(db);
sqlite3_close(db);
[pool release];
}
NSNumber *lastInsertRowId = nil;
if(0 != lastRowId) {
lastInsertRowId = [NSNumber numberWithInteger:lastRowId];
}
return lastInsertRowId;
}
static int singleRowCallback(void *queryValuesVP, int columnCount, char **values, char **columnNames) {
NSMutableDictionary *queryValues = (NSMutableDictionary *)queryValuesVP;
int i;
for(i=0; i<columnCount; i++) {
[queryValues setObject:values[i] ? [NSString stringWithFormat:@"%s",values[i]] : [NSNull null]
forKey:[NSString stringWithFormat:@"%s", columnNames[i]]];
}
return 0;
}
+ (NSString *)selectOneValueSQL:(NSString *)sql {
NSMutableDictionary *queryValues = [NSMutableDictionary dictionary];
[self executeSQL:sql withCallback:singleRowCallback context:queryValues];
NSString *value = nil;
if([queryValues count] == 1) {
value = [[queryValues objectEnumerator] nextObject];
}
return value;
}
+ (NSNumber *)insertWithSQL:(NSString *)sql {
sql = [NSString stringWithFormat:@"BEGIN TRANSACTION; %@; COMMIT TRANSACTION;", sql];
return [self executeSQL:sql withCallback:NULL context:NULL];
}
+ (void)updateWithSQL:(NSString *)sql {
sql = [NSString stringWithFormat:@"BEGIN TRANSACTION; %@; COMMIT TRANSACTION;", sql];
[self executeSQL:sql withCallback:NULL context:nil];
}
@end
**
对此解决方案的任何帮助都是巨大的!
答案 0 :(得分:10)
我认为你遇到的很大一部分问题是你试图过多地简化SQLite3 API。 API不仅用于执行文本SQL查询;准备好的语句和绑定参数是有原因的。您不应该尝试在字符串中插入二进制数据。这只是问问题,特别是如果你的二进制数据中有空值。
要插入blob,您确实需要将sqlite3_bind_blob
与sqlite3_prepare_v2
一起使用。绑定blob时,还需要使用[imgData bytes]
作为blob数据。
你是否正在寻找帮助重建你的API以使这种特殊的图像缓存用例更容易?
修改强>
这是一个使用bind来插入二进制数据的简单示例。假设有一个名为my_table
的表格,其中包含2列:name
类型VARCHAR
和data
类型BLOB
。请注意,我没有测试过,甚至没有尝试过编译,因此可能存在拼写错误或错误。
sqlite3 *database;
// Open a connection to the database given its file path.
if (sqlite3_open("/path/to/sqlite/database.sqlite3", &database) != SQLITE_OK) {
// error handling...
}
// Construct the query and empty prepared statement.
const char *sql = "INSERT INTO `my_table` (`name`, `data`) VALUES (?, ?)";
sqlite3_stmt *statement;
// Prepare the data to bind.
NSData *imageData = UIImagePNGRepresentation([UIImage imageNamed:@"something"]);
NSString *nameParam = @"Some name";
// Prepare the statement.
if (sqlite3_prepare_v2(database, sql, -1, &statement, NULL) == SQLITE_OK) {
// Bind the parameters (note that these use a 1-based index, not 0).
sqlite3_bind_text(statement, 1, nameParam);
sqlite3_bind_blob(statement, 2, [imageData bytes], [imageData length], SQLITE_STATIC);
// SQLITE_STATIC tells SQLite that it doesn't have to worry about freeing the binary data.
}
// Execute the statement.
if (sqlite3_step(statement) != SQLITE_DONE) {
// error handling...
}
// Clean up and delete the resources used by the prepared statement.
sqlite3_finalize(statement);
// Now let's try to query! Just select the data column.
const char *selectSql = "SELECT `data` FROM `my_table` WHERE `name` = ?";
sqlite3_stmt *selectStatement;
if (sqlite3_prepare_v2(database, selectSql, -1, &selectStatement, NULL) == SQLITE_OK) {
// Bind the name parameter.
sqlite3_bind_text(selectStatement, 1, nameParam);
}
// Execute the statement and iterate over all the resulting rows.
while (sqlite3_step(selectStatement) == SQLITE_ROW) {
// We got a row back. Let's extract that BLOB.
// Notice the columns have 0-based indices here.
const void *blobBytes = sqlite3_column_blob(selectStatement, 0);
int blobBytesLength = sqlite3_column_bytes(selectStatement, 0); // Count the number of bytes in the BLOB.
NSData *blobData = [NSData dataWithBytes:blobBytes length:blobBytesLength];
NSLog("Here's that data!\n%@", blobData);
}
// Clean up the select statement
sqlite3_finalize(selectStatement);
// Close the connection to the database.
sqlite3_close(database);