我有这样一个查询:
select distinct Project_Id,keyword,SE_Id from Table1 ;
它返回了将近14.000行。
我还有另一个SQL查询,如下所示:
with DateWithValue as (
SELECT *
FROM DateTable as dt LEFT JOIN Table1 as PK on dt.Date_ID=PK.Load_Date and PK.Project_Id=? and Pk.keyword=? and SE_Id=?
LEFT JOIN Table2 as pr on PK.Project_ID=pr.Project_ID
where PK.Domain is not null and
dt.Date_ID>= (SELECT min(Load_Date) from Table1 where Project_Id=? and keyword=? and SE_Id=? ) and
dt.Date_ID<= (SELECT max(Load_Date) from Table1 where Project_Id=? and keyword=? and SE_Id=? )
--order by Date_ID
)
select * from DateTable as dt Left join DateWithValue on dt.Date_ID=DateWithValue.Date_ID
where DateWithValue.Date_ID is not null
order by dt.Date_ID
在此查询中,?
应该替换为第一个查询的第i个结果。
如何合并这两个查询?你对我有什么想法
更新:我将查询更改如下(为更好分析,我举一个例子):
SELECT
dt.Date_ID
,Pk.keyword
-- ,pr.Company_BK
-- ,pr.Project_URL
,t2.pos_position
,pk.Project_Id
,PK.SE_Id
FROM
DimDate as dt
JOIN
(
SELECT
t1.Project_Id,
t1.keyword,
t1.SE_Id,
Min_Load_Date = MIN(t1.Load_Date),
Max_Load_Date = MAX(t1.Load_Date)
FROM
[RL].[SearchMetrics_ProjectKeyword] t1
where keyword='aktueller gaspreis pro kwh' and Project_Id=383601 and SE_ID=1
GROUP BY
t1.Project_Id,
t1.keyword,
t1.SE_Id
)
as PK
ON dt.Date_ID >= PK.Min_Load_Date
AND dt.Date_ID < PK.Max_Load_Date
--AND PK.Project_Id=?
--AND Pk.keyword=?
--AND SE_Id=?
LEFT JOIN [RL].[SearchMetrics_ProjectKeyword] t2
on Pk.Project_Id=t2.Project_Id and PK.keyword=t2.keyword and PK.SE_Id=t2.SE_Id and t2.Load_Date >= dt.Date_ID and t2.Load_Date <= dt.Date_ID
-- LEFT JOIN MDM.SearchMetrics_Project as pr
-- ON PK.Project_ID=pr.Project_ID
通过此查询,我得到这样的结果:
结构正是我要寻找的结构,但是新的挑战是列pos_positin
,该列有时具有NULL值。但这不应该是这样。
20180406和20180412之间的此列应为19,而20180413和20180423之间的此列应为21
如何通过此查询实现?
更新2:我明白了,这里是解决方法:
with cte as
(
SELECT
dt.Date_ID
,Pk.keyword
-- ,pr.Company_BK
-- ,pr.Project_URL
,t2.pos_position
,pk.Project_Id
,PK.SE_Id
FROM
DimDate as dt
JOIN
(
SELECT
t1.Project_Id,
t1.keyword,
t1.SE_Id,
Min_Load_Date = MIN(t1.Load_Date),
Max_Load_Date = MAX(t1.Load_Date)
FROM
[RL].[SearchMetrics_ProjectKeyword] t1
where keyword='citire gaze' and Project_Id=1458724 and SE_ID=79
GROUP BY
t1.Project_Id,
t1.keyword,
t1.SE_Id
)
as PK
ON dt.Date_ID >= PK.Min_Load_Date
AND dt.Date_ID < PK.Max_Load_Date
--AND PK.Project_Id=?
--AND Pk.keyword=?
--AND SE_Id=?
LEFT JOIN [RL].[SearchMetrics_ProjectKeyword] t2
on Pk.Project_Id=t2.Project_Id and PK.keyword=t2.keyword and PK.SE_Id=t2.SE_Id and t2.Load_Date >= dt.Date_ID and t2.Load_Date <= dt.Date_ID
-- LEFT JOIN MDM.SearchMetrics_Project as pr
-- ON PK.Project_ID=pr.Project_ID
)
select a.Date_ID
,a.keyword
,a.Project_Id
,a.SE_Id
,ISNULL(a.pos_position,x.pos_position) pos_position
from cte a outer apply
(select top 1 pos_position
from cte b
where b.Date_ID<a.Date_ID and
b.Project_Id is not null and
b.pos_position is not null and
a.pos_position is null order by Date_ID desc)x
答案 0 :(得分:1)
这应该可以为您提供所需的东西,而避免大量的性能困扰...
将您变成第一个查询...
-- #first_query...
SELECT
t1.Project_Id,
t1.keyword,
t1.SE_Id,
Min_Load_Date = CONVERT(DATE, MIN(t1.Load_Date)),
Max_Load_Date = CONVERT(DATE(MAX(t1.Load_Date))
FROM
dbo.Table1 t1
GROUP BY
t1.Project_Id,
t1.keyword,
t1.SE_Id;
那么您第二个查询就是这样...
SELECT
*
FROM
dbo.DateTable as dt
JOIN #First_Query as PK
ON dt.Date_ID >= PK.Min_Load_Date
AND dt.Date_ID < DATEADD(DAY, 1, Max_Load_Date)
--AND PK.Project_Id=?
--AND Pk.keyword=?
--AND SE_Id=?
LEFT JOIN Table2 as pr
ON PK.Project_ID=pr.Project_ID;
--where
-- PK.Domain is not null
-- AND dt.Date_ID>= (SELECT min(Load_Date) from Table1 where Project_Id=? and keyword=? and SE_Id=? )
-- AND dt.Date_ID<= (SELECT max(Load_Date) from Table1 where Project_Id=? and keyword=? and SE_Id=? )
--order by Date_ID