我有这样的对象数组
var a = [
{'time' : 1539664755070,'T-1': 23 },
{'time' : 1539665095442,'H-1': 24 },
{'time' : 1539666489560,'T-1': 42 },
{'time' : 1539665095442,'H-1': 27 },
{'time': 1539671682230,'H-1': 40.45,'T-2': 33},
{'time': 1539671682230,'T-2': 30.45,'T-1': 65},
{'time': 1539671682230,'T-2': 42.45,'H-1': 11},
{'time': 1539671682230,'T-1': 50.45,'T-2': 85}
];
我想要这样的数据
data : {
'T-1' : [23,42,50.45],
'T-2' : [33,30.45,85],
'H-1' : [24,27,40.45,11]
}
如何从给定数据中获取此数据?
答案 0 :(得分:0)
const data = a.reduce((acc, row) => {
// Loop over keys of each row.
Object.keys(row)
// Filter out the "time" keys.
.filter((key) => key !== 'time')
// Collect the values by key, storing them in the accumulator.
.forEach((key) => {
if (typeof acc[key] === 'undefined') {
acc[key] = []
}
acc[key].push(row[key])
})
return acc
}, {})
答案 1 :(得分:0)
这是一个解决方案,如果不清楚,请让我知道:
#!/bin/bash
while [ $# -gt 0 ]; do
case "$1" in
-path=*)
directory="${1#*=}"
;;
*)
echo "Invalid args: $@"
exit 1
esac
shift
done
# You can do whatever with $directory here
答案 2 :(得分:0)
您可以将array#reduce
与Object.values()
一起使用,以创建密钥的哈希并添加与之对应的值。然后使用Object.assign()
和spread syntax
创建最终对象。
let data = [ {'time' : 1539664755070,'T-1': 23 }, {'time' : 1539665095442,'H-1': 24 }, {'time' : 1539666489560,'T-1': 42 }, {'time' : 1539665095442,'H-1': 27 }, {'time': 1539671682230,'H-1': 40.45,'T-2': 33}, {'time': 1539671682230,'T-2': 30.45,'T-1': 65},{'time': 1539671682230,'T-2': 42.45,'H-1': 11}, {'time': 1539671682230,'T-1': 50.45,'T-2': 85} ],
result = Object.assign({}, ...Object.values(data.reduce((r, o) => {
let keys = Object.keys(o).filter(k => k !== 'time');
keys.forEach(key => {
r[key] = r[key] || {[key] : []};
r[key][key].push(o[key]);
});
return r;
},{})));
console.log(result);
答案 3 :(得分:0)
使用Map代替Key,Value数组的最佳用例。简化了很多事情。