Question

我已经使用angular将对象数组发送到Api进行后期操作，该操作与3个对象的数组一起进行：

我想要在Java中使用它，所以我将Java中的类初始化为：

SLDto.java

 public class SLDto {

        private LetterDto letterDto;
        private List<DocumentDto> documentDto;
        private List<SelectionCustomOfficeDto> selectionCustomOfficeDto;



        public SLDto() {

        }
//i omitted getters and setters here
    }

LetterDto.java

public class LetterDto {

  private int clkletter;
 private String inOut;
 private String inOutNo;
private String inOutDate;
private String letterIssuedSubBy;
private String letterFile;
private String representativeName;
private int assessmentNo;
private int selectionNo;


public LetterDto() {

}

DocumentDto.java

public class DocumentDto {

    private int docId;
    private String docName;
    private boolean checked;

    public DocumentDto() {

    }
}

SelectionCustomOfficeDto.java

public class SelectionCustomOfficeDto {

 private int id;
 private String fromDate;
 private String  toDate;
 private int consignmentNo;
 private int selectionId;
 private int customOfficeId;
 private String custOfficeName;
 private String selectionName;
}

我需要将客户端对象映射到Api，所以我使用了方法：

 @PostMapping(value = "/letter/create")
        public String postAllOne(@RequestBody SLDto sldto ) {

            //i tried 2ways to see the json data or trace it and assign into 
         respective objects but i am not getting.I tried
        1st method
       System.out.println(sldto.getLetterDto()); //Not working 

       2nd method 
         for(LetterDto letterDto:sldto.getLetterDto()) {
                //it is not allowing me
            }

            return  "success";
        }

不允许我将其映射为：

如何将3json数据分为各自的对象？

[{"inOutNo":"2018-11-12","inOutDate":"2","inOut":"AnnexOne","letterFile":null,"representativeName":null,"assessmentNo":0,"letterIssuedSubBy":null,"selectionNo":8},[{"docId":1,"docName":"proforma invoice","checked":true},{"docId":2,"docName":"Packing list","checked":true}],[{"customOfficeId":"1","fromDate":"2018-11-12","toDate":"2018-11-20","consignmentNo":2,"selectionId":8,"selectionName":"PCS","custOfficeName":"Bhairawa Bhansar"}]]

看到的错误是

我遇到类似

的错误

“ DefaultHandlerExceptionResolver：已解决 [org.springframework.http.converter.HttpMessageNotReadableException： JSON解析错误：无法反序列化的实例 com.ashwin.springsecurityangular.dto.SLDto脱离START_ARRAY令牌；嵌套异常为 com.fasterxml.jackson.databind.exc.MismatchedInputException：无法反序列化com.ashwin.springsecurityangular.dto.SLD的实例到 START_ARRAY令牌”

Answer 1

您应该像下面的json这样发送：

 {
    "letterDto" : {"clkletter": "as" }, // your other properties,
    "documentDto": [{"docId" : 1},{"docId" : 2}]// your other properties inside json object
    "selectionCustomOfficeDto": [{"id": 12},{"id": 121}]// your other properties inside json object

 }

以下是供您参考的示例，outer类具有List<Inner2>，List<Inner3>和Inner1

Json看起来像

{
    "inner1": {"f1": "v1","f2": "v2"},
    "inner2s": [{"f3": "v3","f4": "v4"},{"f3": "v5","f4": "v6"}],

    "inner3s": [{"f5": "v7","f6": "v8"},{"f5": "v9","f6": "v10"}]
}

PoJo类

class Outer{
        Inner1 inner1;
        List<Inner2> inner2s;
        List<Inner3> inner3s;

        public Inner1 getInner1() {
            return inner1;
        }
        public void setInner1(Inner1 inner1) {
            this.inner1 = inner1;
        }
        public List<Inner2> getInner2s() {
            return inner2s;
        }
        public void setInner2s(List<Inner2> inner2s) {
            this.inner2s = inner2s;
        }
        public List<Inner3> getInner3s() {
            return inner3s;
        }
        public void setInner3s(List<Inner3> inner3s) {
            this.inner3s = inner3s;
        }

    }

     class Inner1{

        String f1;
        String f2;
        public String getF1() {
            return f1;
        }
        public void setF1(String f1) {
            this.f1 = f1;
        }
        public String getF2() {
            return f2;
        }
        public void setF2(String f2) {
            this.f2 = f2;
        }



    }
     class Inner2{
        String f3;
        String f4;
        public String getF3() {
            return f3;
        }
        public void setF3(String f3) {
            this.f3 = f3;
        }
        public String getF4() {
            return f4;
        }
        public void setF4(String f4) {
            this.f4 = f4;
        }


    }

     class Inner3{
        String f5;
        String f6;
        public String getF5() {
            return f5;
        }
        public void setF5(String f5) {
            this.f5 = f5;
        }
        public String getF6() {
            return f6;
        }
        public void setF6(String f6) {
            this.f6 = f6;
        }


    }

请求映射

@RequestMapping(value="/test",produces=MediaType.APPLICATION_JSON_VALUE,method= {RequestMethod.POST})
    public String post(@RequestBody Outer outer) {
        LOGGER.debug("Getting the logged in cutomer details" +outer);
        Customer customer1 = new Customer("1", "customer1", "Sample@cust1.com");
        LOGGER.info("The customer details are " + customer1);
        return "done!!";
    }

Answer 2

您当前的POST方法处理程序期望使用以下格式的JSON对象：

{
    "letterDto" : {
        "clkletter" : 1, 
        "inOut" : "Someting",
        ...
    },
    "documentDto" : [
        {
            "docId" : 1,
            "docName" : "Name",
            "checked" : true
        } ,
        {
            "docId" : 2,
            "docName" : "Name 2",
            "checked" : false
        }
    ],
    "selectionCustomOfficeDto" : [
        {
            "id" : 1,
            "fromDate" : "someDate,
            ...
        },
        {
            "id" : 2,
            "fromDate" : "someDate2,
            ...
        }
    ]

}

但是目前，您正在发送JSON数组：

[
    "letterDto" : {<letter properties>},
    [
        {
            <document properties>
        },
        {
            <document properties>
        }
    ],
    [
        {
            <selection custom office properties>
        }
    ]
]

解决此问题后，您将能够遍历slDto.getDocumentDto和slDto.getSelectionCustomOfficeDto，因为它们是slDto对象中包含的唯一 collections ，因此：

slDto.getSelectionCustomOfficeDto.forEach(s -> doSomething(s));

slDto.getDocumentDto.forEach(d -> doSomething(d));

您可以像这样调用Letter的方法：

slDto.getLetterDto.getId();

Answer 3

嗨，请确保您的JSON请求如下：

{
    "letterDto" : {
        "clkletter" : 1,
        "inOut" : "some-string-value",
        "inOutNo" : "some-string-value",
        "inOutDate" : "some-string-value",
        "letterIssuedSubBy" : "some-string-value",
        "letterFile" : "some-string-value",
        "representativeName" : "some-string-value",
        "assessmentNo" : 1,
        "selectionNo" : 1
    },
    "documentDto" : [
        {
            "docId" : 1,
            "docName" : "some-doc-name",
            "checked" : true
        },
        {
            "docId" : 2,
            "docName" : "some-doc-name",
            "checked" : true
        },
        {
            "docId" : 3,
            "docName" : "some-doc-name",
            "checked" : true
        }
    ],
    "selectionCustomOfficeDto" : [
        {
            "id" : 1,
            "fromDate" : "some-date",
            "toDate" : "some-date",
            "consignmentNo" : 1,
            "selectionId" : 1,
            "customOfficeId" : 1,
            "custOfficeName" : "some-office-name",
            "selectionName" : "some-selection-name"
        },
        {
            "id" : 2,
            "fromDate" : "some-date",
            "toDate" : "some-date",
            "consignmentNo" : 1,
            "selectionId" : 1,
            "customOfficeId" : 1,
            "custOfficeName" : "some-office-name",
            "selectionName" : "some-selection-name"
        },
        {
            "id" : 3,
            "fromDate" : "some-date",
            "toDate" : "some-date",
            "consignmentNo" : 1,
            "selectionId" : 1,
            "customOfficeId" : 1,
            "custOfficeName" : "some-office-name",
            "selectionName" : "some-selection-name"
        }
    ]
}

此外，在代码块中，

for(LetterDto letterDto:sldto.getLetterDto()) {
//it is not allowing me
}

此处sldto.getLetterDto()返回一个LetterDto Object而不是List，因此不可能进行迭代。

希望有帮助！

如何在Java中迭代对象的arrayList？

3 个答案: