角度-将多个子组件表单检查为肮脏

时间:2018-11-16 06:21:15

标签: javascript angular typescript angular-components

我有一堆子元素包含form-表单的值将从父子元素发送-我在父子对象中循环了子子元素并将数据传递给了子元素

子组件

<form #formType="ngForm">
    <div class="col-lg-4" *ngFor="let data of productSizes; let i = index;">
        <div class="inlinediv" *ngFor="let item of data.ItemDetails">
            <div class="marginright15 inlinediv">
                <ng-container *ngIf="item.Foundation">
                    <b>{{item.Size.toUpperCase()}}</b><br />
                    <input *ngFor="let val of item.Foundation" type="text" appNumbericInput maxlength="4" [(ngModel)]="val.Val" class="inputcustom text-right" [disabled]="(val.Val == null ? true : false) || disableChecker" (input)="enableSave=true" />
                </ng-container>
            </div>
        </div>
    </div>
</form>

子Component.ts

@Component({
    selector: 'app-base-mattress',
    templateUrl: './base-mattress.component.html',
    styleUrls: ['./base-mattress.component.css']
})

export class BaseMattressComponent implements OnInit {
    @Input() productSizes: IItemDetails[];
    @ViewChild('formType') formVariable: NgForm;
    blobURL: string = environment.blobURL;
    constructor() {}
    ngOnInit() {}
}

父组件html

<ng-container *ngFor="let slot of slotRequests; let j = index;">
    <ng-container *ngIf="slot.ItemGrouping.toLowerCase() === 'mattress'">
        <ng-container *ngFor="let data of slotRequests[j].Data; let i = index;">
            <app-base-mattress [productSizes]="data"></app-base-mattress>
        </ng-container>
    </ng-container>
</ng-container>

现在我的问题是我想读取子组件的表单变量? 我不想订阅某个服务,并检查form是否脏了,我已经尝试了很多次,但都没用。

我试图用这样的模板引用变量来映射我的孩子 <app-base-mattress [productSizes]="data" #childData></app-base-mattress> 但似乎我正在循环子组件,因此它似乎不充当特定组件的参考变量-请帮助我找出如何读取子组件形式变量

StackBlitz的工作版本

谢谢!

2 个答案:

答案 0 :(得分:1)

在顶级组件中使用表单元素

<form #formType="ngForm">
    <ng-container *ngFor="let slot of slotRequests; let j = index;">
        <ng-container *ngIf="slot.ItemGrouping.toLowerCase() === 'mattress'">
            <ng-container>

                <div *ngFor="let data of slotRequests[j].Data; let i = index;">
                    <app-base-mattress [productSizes]="data.ItemDetails"></app-base-mattress>
                </div>

            </ng-container>
        </ng-container>
    </ng-container>
</form>

使用viewproviders提供controncontainer,它是form的超类。将现有的ngForm组组一起用于表单

import { Component, OnInit, ViewChild, Input } from '@angular/core';
import { NgForm, ControlContainer } from '@angular/forms'

@Component({
  selector: 'app-base-mattress',
  templateUrl: './base-mattress.component.html',
  styleUrls: ['./base-mattress.component.css'],
  viewProviders: [{ provide: ControlContainer, useExisting: NgForm }]
})
export class BaseMattressComponent implements OnInit {
  @Input() productSizes: any[];

  constructor() { }

  ngOnInit() {
  }

}

示例:https://stackblitz.com/edit/angular-ch5yh2

答案 1 :(得分:0)

您可以这样做:

parent.component.html

<app-base-mattress #childCmp [productSizes]="data"></app-base-mattress>

parent.component.ts

@ViewChildren('childCmp ')
childCmps: QueryList<BaseMattressComponent>;

然后遍历它们以获得所需的结果

this.childCmps.forEach((item) => {
...
});