Question

SELECT COUNT(*) AS customer, t.state
  FROM tbl_parcel_item t
 WHERE t.courier_name='Tnt'
   AND t.date = '2018-03-12'
   AND t.ship_status NOT IN (0,1,9,10)
 GROUP BY t.state`

基于上面的sql，结果将是： enter image description here 如何使它得到上面的结果的总和，例如： enter image description here

Answer 1

使用with rollup：

SELECT COUNT(*) AS customer, t.state`
FROM tbl_parcel_item t
WHERE t.courier_name = 'Tnt' AND
      t.date = '2018-03-12' AND
      t.ship_status NOT IN (0, 1, 9, 10)
GROUP BY t.state WITH ROLLUP;

Answer 2

全部使用联合：

`SELECT COUNT(*) AS customer, t.state`
`FROM tbl_parcel_item t`
`WHERE t.courier_name='Tnt'`
`AND t.date = '2018-03-12'`
`AND t.ship_status NOT IN (0,1,9,10)`
`GROUP BY t.state`
`UNION ALL`
`SELECT COUNT(*) AS customer, 'Total' as state`
`FROM tbl_parcel_item t`
`WHERE t.courier_name='Tnt'`
`AND t.date = '2018-03-12'`
`AND t.ship_status NOT IN (0,1,9,10)`

Answer 3

在查询上方添加另一个查询，如下所示：

Select sum(customer) as Total
FROM
(
SELECT COUNT(*) AS customer, t.state`
FROM tbl_parcel_item t
WHERE t.courier_name = 'Tnt' AND
      t.date = '2018-03-12' AND
      t.ship_status NOT IN (0, 1, 9, 10)
GROUP BY t.state
)a;

Answer 4

使用ROLLUP：

SELECT
    COALESCE(t.state, 'TOTAL') AS state,
    COUNT(*) AS customer
FROM tbl_parcel_item t
WHERE
    t.courier_name = 'Tnt' AND
    t.date = '2018-03-12'  AND
    t.ship_status NOT IN (0,1,9,10)
GROUP BY t.state WITH ROLLUP;

Answer 5

01）WITH ROLLUP如其他答案所述

02）使用联合查询

  SELECT  t.state, COUNT(*) AS customer FROM tbl_parcel_item t WHERE t.courier_name='Tnt' AND t.date = '2018-03-12' AND t.ship_status NOT IN (0,1,9,10) GROUP BY t.state
  UNION 
  SELECT  'Total', COUNT(*) AS customer FROM tbl_parcel_item t WHERE t.courier_name='Tnt' AND t.date = '2018-03-12' AND t.ship_status NOT IN (0,1,9,10)

分组后如何获得总计

5 个答案: