Question

我是Node \ JS的新手，并且坚持如何在创建新集合的集合中合并匹配元素和迭代不匹配元素。到目前为止，我已经使用lodash将下面粘贴的数据分组（“分组输入”），但是无法弄清楚如何获得所需的输出。

我愿意使用lodash \ underscore \ javascript或与Node兼容的任何其他库。

感谢您的帮助和建议。

Grouped Input:

[ { mod_AccountNumber: '0001',
    mod_Id: '123456',
    mod_LastName: 'SMITH',
    mod_FirstName: 'NANCY',
    mod_AppointmentLocation: 'ROOM10',
    mod_AppointmentDate: '10/26/18',
    mod_AppointmentTime: '0900' },
  { mod_AccountNumber: '0001',
    mod_Id: '123456',
    mod_LastName: 'SMITH',
    mod_FirstName: 'NANCY',
    mod_AppointmentLocation: 'ROOM11',
    mod_AppointmentDate: '10/26/18',
    mod_AppointmentTime: '0930' },
  { mod_AccountNumber: '0001',
    mod_Id: '654321',
    mod_LastName: 'JONES',
    mod_FirstName: 'NATASHA',
    mod_AppointmentLocation: 'ROOM11',
    mod_AppointmentDate: '10/26/18',
    mod_AppointmentTime: '0930' },
  { mod_AccountNumber: '0001',
    mod_Id: '654321',
    mod_LastName: 'JONES',
    mod_FirstName: 'NATASHA',
    mod_AppointmentLocation: 'ROOM12',
    mod_AppointmentDate: '10/26/18',
    mod_AppointmentTime: '1015' }
]

Desired Output:

[ { mod_AccountNumber: '0001',
    mod_Id: '123456',
    mod_LastName: 'SMITH',
    mod_FirstName: 'NANCY',
    mod_AppointmentLocation_1: 'ROOM10',
    mod_AppointmentTime_1:'0900',
    mod_AppointmentLocation_2: 'ROOM11',
    mod_AppointmentTime_2:'0930' },
  { mod_AccountNumber: '0001',
    mod_Id: '654321',
    mod_LastName: 'JONES',
    mod_FirstName: 'NATASHA',
    mod_AppointmentLocation_1: 'ROOM11',
    mod_AppointmentTime_1:'0930',
    mod_AppointmentLocation_2: 'ROOM12',
    mod_AppointmentTime_2:'1015' }
]

Answer 1

const {groupBy, values, merge} = require('lodash');
// input...
const output = values(
    groupBy(input, 'id')
).map(chunks => merge(...chunks));

Answer 2

总体上更好的方法是将这些日期/时间/位置转换为数组。但是鉴于当前的问题，可以这样做：

const data = [{ mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM10', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0900' }, { mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM12', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '1015' } ]

const result = _(data)
 .groupBy('mod_Id')
 .values()
 .map(x => _.values(_.transform(x, (r,c,i) => {
   r[c.mod_Id] = _.extend(r[c.mod_Id], {
   mod_Id: c.mod_Id,
   mod_AccountNumber: c.mod_AccountNumber,
   mod_LastName: c.mod_LastName,
   mod_FirstName: c.mod_FirstName,
   [`mod_AppointmentLocation${i+1}`]: c.mod_AppointmentLocation,
   [`mod_AppointmentDate${i+1}`]: c.mod_AppointmentDate,
   [`mod_AppointmentTime${i+1}`]: c.mod_AppointmentTime,
 })}, {})))
 .flatten()
 .value()

console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>

想法是首先将mod_Id分组，然后将values map穿过它们，然后transform使其成为一个对象。由于您已恢复为对象形式，因此可以得到values，最后得到flatten数组。

更简单的方法是将 ES6 与以下内容一起使用：

const data = [{ mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM10', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0900' }, { mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM12', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '1015' } ]

const result = Object.values(data.reduce((r, c, i) => {
  let _x = r[c.mod_Id] ? r[c.mod_Id]._x : 0
  _x++
  r[c.mod_Id] = Object.assign(r[c.mod_Id] || {}, {
    mod_Id: c.mod_Id,
    mod_AccountNumber: c.mod_AccountNumber,
    mod_LastName: c.mod_LastName,
    mod_FirstName: c.mod_FirstName,
    [`mod_AppointmentLocation${_x}`]: c.mod_AppointmentLocation,
    [`mod_AppointmentDate${_x}`]: c.mod_AppointmentDate,
    [`mod_AppointmentTime${_x}`]: c.mod_AppointmentTime,
    _x
  })
  return r
}, {})).map(({_x, ...rest}) => rest)
console.log(result)

唯一需要注意的是，这种方法并不纯正，因为它通过使用_x属性对对象进行更改来跟踪当前商品编号，该属性最后通过map剥离了。 >

如果您想考虑采用数组思想，那么事情会变得简单得多：

const data = [{ mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM10', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0900' }, { mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM12', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '1015' } ]

const result = _.chain(data)
  .reduce((r,c,i) => {
  r[c.mod_Id] = r[c.mod_Id] ? r[c.mod_Id] : {
    mod_Id: c.mod_Id,
    mod_AccountNumber: c.mod_AccountNumber,
    mod_LastName: c.mod_LastName,
    mod_FirstName: c.mod_FirstName,
    schedule: []
  }
  r[c.mod_Id].schedule.push({
    mod_AppointmentLocation: c.mod_AppointmentLocation,
    mod_AppointmentDate: c.mod_AppointmentDate,
    mod_AppointmentTime: c.mod_AppointmentTime
  })
  return r
 }, {})
 .values()
 .value()
 
console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>

合并匹配元素，并迭代和分离出集合中不匹配的元素

2 个答案: