Question

我正在尝试基于此String（它是一个SQL创建查询）在Python中构建列值和声明类型的列表：

creation_sql = '''CREATE TABLE "objects_users" (
    "id" serial NOT NULL PRIMARY KEY, 
    "clientID" integer NOT NULL, 
    "email" varchar(100) NOT NULL, 
    "first_name" varchar(100) NOT NULL, 
    "last_name" varchar(100) NOT NULL, 
    "phone" varchar(100) NOT NULL, 
    "password" varchar(100) NOT NULL, 
    "type" varchar(100) NOT NULL, 
    "date_created" timestamp with time zone NOT NULL, 
    "active" varchar(100) NOT NULL);'''

我已经像这样解析出表达式中的引用值：

def parse(creation_query):

    quoted_values = re.compile('"[^"]*"')
    values = quoted_values.findall(creation_sql)

    column_names = []
    for value in values:
        column_names.append(value)

    table_name = column_names[0]
    column_names = [names.replace('"','') for names in column_names]

    del column_names[0]         # this will be table name
    print(table_name)
    print(column_names)

如何解析每一行的SQL类型值？

例如，我已经在列表中收集了id和clientID。现在，我要在列表中声明serial NOT NULL PRIMARY KEY和integer NOT NULL等。

如何完成这种类型的解析？我决定是最好的，但我可以自己弄清楚，我只需要正则表达式

更新

以下是更新的代码，该代码根据creation_sql语句为我提供了我需要的所有内容的字典：

import re

creation_sql = '''CREATE TABLE "objects_users" (
    "id" serial NOT NULL PRIMARY KEY, 
    "clientID" integer NOT NULL, 
    "email" varchar(100) NOT NULL, 
    "first_name" varchar(100) NOT NULL, 
    "last_name" varchar(100) NOT NULL, 
    "phone" varchar(100) NOT NULL, 
    "password" varchar(100) NOT NULL, 
    "type" varchar(100) NOT NULL, 
    "date_created" timestamp with time zone NOT NULL, 
    "active" varchar(100) NOT NULL);'''

def parse(creation_query):

    quoted_values = re.compile('"[^"]*"')
    table_name = quoted_values.findall(creation_query)[0]

    dictionary_values = dict(re.findall('"(.*?)"\s+(.+)[,)]', creation_query))
    dictionary_values['table_name'] = table_name.replace('"','')

    return dictionary_values

d = parse(creation_sql)
print(d.get('table_name'))
for key, item in d.items():
    if key != 'table_name':
        print(key + ":"+ item)

Answer 1

尝试一下：

import re
r = re.findall('"(.*?)"\s+(.+)?[,)]', creation_sql)

print(dict(r))

字符串解析的正则表达式

1 个答案: